Stop the analysis pass in Loopy's redraw routine from being
[sgt/puzzles] / untangle.c
CommitLineData
9d6c3859 1/*
2 * untangle.c: Game about planar graphs. You are given a graph
3 * represented by points and straight lines, with some lines
4 * crossing; your task is to drag the points into a configuration
5 * where none of the lines cross.
6 *
7 * Cloned from a Flash game called `Planarity', by John Tantalo.
8 * <http://home.cwru.edu/~jnt5/Planarity> at the time of writing
9 * this. The Flash game had a fixed set of levels; my added value,
10 * as usual, is automatic generation of random games to order.
11 */
12
13/*
14 * TODO:
15 *
9d6c3859 16 * - Any way we can speed up redraws on GTK? Uck.
17c75e70 17 *
18 * - It would be nice if we could somehow auto-detect a real `long
19 * long' type on the host platform and use it in place of my
20 * hand-hacked int64s. It'd be faster and more reliable.
9d6c3859 21 */
22
23#include <stdio.h>
24#include <stdlib.h>
25#include <string.h>
26#include <assert.h>
27#include <ctype.h>
28#include <math.h>
29
30#include "puzzles.h"
31#include "tree234.h"
32
33#define CIRCLE_RADIUS 6
34#define DRAG_THRESHOLD (CIRCLE_RADIUS * 2)
35#define PREFERRED_TILESIZE 64
36
8eef6b92 37#define FLASH_TIME 0.30F
9d6c3859 38#define ANIM_TIME 0.13F
39#define SOLVEANIM_TIME 0.50F
40
41enum {
42 COL_BACKGROUND,
43 COL_LINE,
0d98f76f 44#ifdef SHOW_CROSSINGS
45 COL_CROSSEDLINE,
46#endif
9d6c3859 47 COL_OUTLINE,
48 COL_POINT,
49 COL_DRAGPOINT,
50 COL_NEIGHBOUR,
8eef6b92 51 COL_FLASH1,
52 COL_FLASH2,
9d6c3859 53 NCOLOURS
54};
55
56typedef struct point {
57 /*
58 * Points are stored using rational coordinates, with the same
59 * denominator for both coordinates.
60 */
42159ec6 61 long x, y, d;
9d6c3859 62} point;
63
64typedef struct edge {
65 /*
66 * This structure is implicitly associated with a particular
67 * point set, so all it has to do is to store two point
68 * indices. It is required to store them in the order (lower,
69 * higher), i.e. a < b always.
70 */
71 int a, b;
72} edge;
73
74struct game_params {
75 int n; /* number of points */
76};
77
78struct graph {
79 int refcount; /* for deallocation */
80 tree234 *edges; /* stores `edge' structures */
81};
82
83struct game_state {
84 game_params params;
85 int w, h; /* extent of coordinate system only */
86 point *pts;
0d98f76f 87#ifdef SHOW_CROSSINGS
88 int *crosses; /* mark edges which are crossed */
89#endif
9d6c3859 90 struct graph *graph;
91 int completed, cheated, just_solved;
92};
93
94static int edgecmpC(const void *av, const void *bv)
95{
96 const edge *a = (const edge *)av;
97 const edge *b = (const edge *)bv;
98
99 if (a->a < b->a)
100 return -1;
101 else if (a->a > b->a)
102 return +1;
103 else if (a->b < b->b)
104 return -1;
105 else if (a->b > b->b)
106 return +1;
107 return 0;
108}
109
110static int edgecmp(void *av, void *bv) { return edgecmpC(av, bv); }
111
112static game_params *default_params(void)
113{
114 game_params *ret = snew(game_params);
115
116 ret->n = 10;
117
118 return ret;
119}
120
121static int game_fetch_preset(int i, char **name, game_params **params)
122{
123 game_params *ret;
124 int n;
125 char buf[80];
126
127 switch (i) {
128 case 0: n = 6; break;
129 case 1: n = 10; break;
130 case 2: n = 15; break;
131 case 3: n = 20; break;
132 case 4: n = 25; break;
133 default: return FALSE;
134 }
135
136 sprintf(buf, "%d points", n);
137 *name = dupstr(buf);
138
139 *params = ret = snew(game_params);
140 ret->n = n;
141
142 return TRUE;
143}
144
145static void free_params(game_params *params)
146{
147 sfree(params);
148}
149
150static game_params *dup_params(game_params *params)
151{
152 game_params *ret = snew(game_params);
153 *ret = *params; /* structure copy */
154 return ret;
155}
156
157static void decode_params(game_params *params, char const *string)
158{
159 params->n = atoi(string);
160}
161
162static char *encode_params(game_params *params, int full)
163{
164 char buf[80];
165
166 sprintf(buf, "%d", params->n);
167
168 return dupstr(buf);
169}
170
171static config_item *game_configure(game_params *params)
172{
173 config_item *ret;
174 char buf[80];
175
176 ret = snewn(3, config_item);
177
178 ret[0].name = "Number of points";
179 ret[0].type = C_STRING;
180 sprintf(buf, "%d", params->n);
181 ret[0].sval = dupstr(buf);
182 ret[0].ival = 0;
183
184 ret[1].name = NULL;
185 ret[1].type = C_END;
186 ret[1].sval = NULL;
187 ret[1].ival = 0;
188
189 return ret;
190}
191
192static game_params *custom_params(config_item *cfg)
193{
194 game_params *ret = snew(game_params);
195
196 ret->n = atoi(cfg[0].sval);
197
198 return ret;
199}
200
201static char *validate_params(game_params *params, int full)
202{
203 if (params->n < 4)
204 return "Number of points must be at least four";
205 return NULL;
206}
207
17c75e70 208/* ----------------------------------------------------------------------
209 * Small number of 64-bit integer arithmetic operations, to prevent
210 * integer overflow at the very core of cross().
211 */
212
213typedef struct {
214 long hi;
215 unsigned long lo;
216} int64;
217
218#define greater64(i,j) ( (i).hi>(j).hi || ((i).hi==(j).hi && (i).lo>(j).lo))
219#define sign64(i) ((i).hi < 0 ? -1 : (i).hi==0 && (i).lo==0 ? 0 : +1)
220
986cc2de 221static int64 mulu32to64(unsigned long x, unsigned long y)
17c75e70 222{
223 unsigned long a, b, c, d, t;
224 int64 ret;
225
226 a = (x & 0xFFFF) * (y & 0xFFFF);
227 b = (x & 0xFFFF) * (y >> 16);
228 c = (x >> 16) * (y & 0xFFFF);
229 d = (x >> 16) * (y >> 16);
230
231 ret.lo = a;
232 ret.hi = d + (b >> 16) + (c >> 16);
233 t = (b & 0xFFFF) << 16;
234 ret.lo += t;
235 if (ret.lo < t)
236 ret.hi++;
237 t = (c & 0xFFFF) << 16;
238 ret.lo += t;
239 if (ret.lo < t)
240 ret.hi++;
241
242#ifdef DIAGNOSTIC_VIA_LONGLONG
243 assert(((unsigned long long)ret.hi << 32) + ret.lo ==
244 (unsigned long long)x * y);
245#endif
246
247 return ret;
248}
249
986cc2de 250static int64 mul32to64(long x, long y)
17c75e70 251{
252 int sign = +1;
253 int64 ret;
254#ifdef DIAGNOSTIC_VIA_LONGLONG
255 long long realret = (long long)x * y;
256#endif
257
258 if (x < 0)
259 x = -x, sign = -sign;
260 if (y < 0)
261 y = -y, sign = -sign;
262
263 ret = mulu32to64(x, y);
264
265 if (sign < 0) {
266 ret.hi = -ret.hi;
267 ret.lo = -ret.lo;
268 if (ret.lo)
269 ret.hi--;
270 }
271
272#ifdef DIAGNOSTIC_VIA_LONGLONG
273 assert(((unsigned long long)ret.hi << 32) + ret.lo == realret);
274#endif
275
276 return ret;
277}
278
986cc2de 279static int64 dotprod64(long a, long b, long p, long q)
17c75e70 280{
281 int64 ab, pq;
282
283 ab = mul32to64(a, b);
284 pq = mul32to64(p, q);
285 ab.hi += pq.hi;
286 ab.lo += pq.lo;
287 if (ab.lo < pq.lo)
288 ab.hi++;
289 return ab;
290}
291
9d6c3859 292/*
293 * Determine whether the line segments between a1 and a2, and
294 * between b1 and b2, intersect. We count it as an intersection if
295 * any of the endpoints lies _on_ the other line.
296 */
297static int cross(point a1, point a2, point b1, point b2)
298{
17c75e70 299 long b1x, b1y, b2x, b2y, px, py;
300 int64 d1, d2, d3;
9d6c3859 301
302 /*
303 * The condition for crossing is that b1 and b2 are on opposite
304 * sides of the line a1-a2, and vice versa. We determine this
305 * by taking the dot product of b1-a1 with a vector
306 * perpendicular to a2-a1, and similarly with b2-a1, and seeing
307 * if they have different signs.
308 */
309
310 /*
311 * Construct the vector b1-a1. We don't have to worry too much
312 * about the denominator, because we're only going to check the
313 * sign of this vector; we just need to get the numerator
314 * right.
315 */
316 b1x = b1.x * a1.d - a1.x * b1.d;
317 b1y = b1.y * a1.d - a1.y * b1.d;
318 /* Now construct b2-a1, and a vector perpendicular to a2-a1,
319 * in the same way. */
320 b2x = b2.x * a1.d - a1.x * b2.d;
321 b2y = b2.y * a1.d - a1.y * b2.d;
322 px = a1.y * a2.d - a2.y * a1.d;
323 py = a2.x * a1.d - a1.x * a2.d;
17c75e70 324 /* Take the dot products. Here we resort to 64-bit arithmetic. */
325 d1 = dotprod64(b1x, px, b1y, py);
326 d2 = dotprod64(b2x, px, b2y, py);
9d6c3859 327 /* If they have the same non-zero sign, the lines do not cross. */
17c75e70 328 if ((sign64(d1) > 0 && sign64(d2) > 0) ||
329 (sign64(d1) < 0 && sign64(d2) < 0))
9d6c3859 330 return FALSE;
331
332 /*
333 * If the dot products are both exactly zero, then the two line
334 * segments are collinear. At this point the intersection
335 * condition becomes whether or not they overlap within their
336 * line.
337 */
17c75e70 338 if (sign64(d1) == 0 && sign64(d2) == 0) {
9d6c3859 339 /* Construct the vector a2-a1. */
340 px = a2.x * a1.d - a1.x * a2.d;
341 py = a2.y * a1.d - a1.y * a2.d;
342 /* Determine the dot products of b1-a1 and b2-a1 with this. */
17c75e70 343 d1 = dotprod64(b1x, px, b1y, py);
344 d2 = dotprod64(b2x, px, b2y, py);
9d6c3859 345 /* If they're both strictly negative, the lines do not cross. */
17c75e70 346 if (sign64(d1) < 0 && sign64(d2) < 0)
9d6c3859 347 return FALSE;
348 /* Otherwise, take the dot product of a2-a1 with itself. If
349 * the other two dot products both exceed this, the lines do
350 * not cross. */
17c75e70 351 d3 = dotprod64(px, px, py, py);
352 if (greater64(d1, d3) && greater64(d2, d3))
9d6c3859 353 return FALSE;
354 }
355
356 /*
357 * We've eliminated the only important special case, and we
358 * have determined that b1 and b2 are on opposite sides of the
359 * line a1-a2. Now do the same thing the other way round and
360 * we're done.
361 */
362 b1x = a1.x * b1.d - b1.x * a1.d;
363 b1y = a1.y * b1.d - b1.y * a1.d;
364 b2x = a2.x * b1.d - b1.x * a2.d;
365 b2y = a2.y * b1.d - b1.y * a2.d;
366 px = b1.y * b2.d - b2.y * b1.d;
367 py = b2.x * b1.d - b1.x * b2.d;
17c75e70 368 d1 = dotprod64(b1x, px, b1y, py);
369 d2 = dotprod64(b2x, px, b2y, py);
370 if ((sign64(d1) > 0 && sign64(d2) > 0) ||
371 (sign64(d1) < 0 && sign64(d2) < 0))
9d6c3859 372 return FALSE;
373
374 /*
375 * The lines must cross.
376 */
377 return TRUE;
378}
379
380static unsigned long squarert(unsigned long n) {
381 unsigned long d, a, b, di;
382
383 d = n;
384 a = 0;
1ad942e7 385 b = 1L << 30; /* largest available power of 4 */
9d6c3859 386 do {
387 a >>= 1;
388 di = 2*a + b;
389 if (di <= d) {
390 d -= di;
391 a += b;
392 }
393 b >>= 2;
394 } while (b);
395
396 return a;
397}
398
399/*
400 * Our solutions are arranged on a square grid big enough that n
401 * points occupy about 1/POINTDENSITY of the grid.
402 */
403#define POINTDENSITY 3
404#define MAXDEGREE 4
405#define COORDLIMIT(n) squarert((n) * POINTDENSITY)
406
407static void addedge(tree234 *edges, int a, int b)
408{
409 edge *e = snew(edge);
410
411 assert(a != b);
412
413 e->a = min(a, b);
414 e->b = max(a, b);
415
416 add234(edges, e);
417}
418
419static int isedge(tree234 *edges, int a, int b)
420{
421 edge e;
422
423 assert(a != b);
424
425 e.a = min(a, b);
426 e.b = max(a, b);
427
428 return find234(edges, &e, NULL) != NULL;
429}
430
431typedef struct vertex {
432 int param;
433 int vindex;
434} vertex;
435
436static int vertcmpC(const void *av, const void *bv)
437{
438 const vertex *a = (vertex *)av;
439 const vertex *b = (vertex *)bv;
440
441 if (a->param < b->param)
442 return -1;
443 else if (a->param > b->param)
444 return +1;
445 else if (a->vindex < b->vindex)
446 return -1;
447 else if (a->vindex > b->vindex)
448 return +1;
449 return 0;
450}
451static int vertcmp(void *av, void *bv) { return vertcmpC(av, bv); }
452
453/*
454 * Construct point coordinates for n points arranged in a circle,
455 * within the bounding box (0,0) to (w,w).
456 */
457static void make_circle(point *pts, int n, int w)
458{
42159ec6 459 long d, r, c, i;
9d6c3859 460
461 /*
462 * First, decide on a denominator. Although in principle it
463 * would be nice to set this really high so as to finely
464 * distinguish all the points on the circle, I'm going to set
465 * it at a fixed size to prevent integer overflow problems.
466 */
467 d = PREFERRED_TILESIZE;
468
469 /*
470 * Leave a little space outside the circle.
471 */
472 c = d * w / 2;
473 r = d * w * 3 / 7;
474
475 /*
476 * Place the points.
477 */
478 for (i = 0; i < n; i++) {
479 double angle = i * 2 * PI / n;
480 double x = r * sin(angle), y = - r * cos(angle);
42159ec6 481 pts[i].x = (long)(c + x + 0.5);
482 pts[i].y = (long)(c + y + 0.5);
9d6c3859 483 pts[i].d = d;
484 }
485}
486
487static char *new_game_desc(game_params *params, random_state *rs,
488 char **aux, int interactive)
489{
42159ec6 490 int n = params->n, i;
491 long w, h, j, k, m;
9d6c3859 492 point *pts, *pts2;
42159ec6 493 long *tmp;
9d6c3859 494 tree234 *edges, *vertices;
495 edge *e, *e2;
496 vertex *v, *vs, *vlist;
497 char *ret;
498
499 w = h = COORDLIMIT(n);
500
501 /*
502 * Choose n points from this grid.
503 */
504 pts = snewn(n, point);
42159ec6 505 tmp = snewn(w*h, long);
9d6c3859 506 for (i = 0; i < w*h; i++)
507 tmp[i] = i;
508 shuffle(tmp, w*h, sizeof(*tmp), rs);
509 for (i = 0; i < n; i++) {
510 pts[i].x = tmp[i] % w;
511 pts[i].y = tmp[i] / w;
512 pts[i].d = 1;
513 }
514 sfree(tmp);
515
516 /*
517 * Now start adding edges between the points.
518 *
519 * At all times, we attempt to add an edge to the lowest-degree
520 * vertex we currently have, and we try the other vertices as
521 * candidate second endpoints in order of distance from this
522 * one. We stop as soon as we find an edge which
523 *
524 * (a) does not increase any vertex's degree beyond MAXDEGREE
525 * (b) does not cross any existing edges
526 * (c) does not intersect any actual point.
527 */
528 vs = snewn(n, vertex);
529 vertices = newtree234(vertcmp);
530 for (i = 0; i < n; i++) {
531 v = vs + i;
532 v->param = 0; /* in this tree, param is the degree */
533 v->vindex = i;
534 add234(vertices, v);
535 }
536 edges = newtree234(edgecmp);
537 vlist = snewn(n, vertex);
538 while (1) {
539 int added = FALSE;
540
541 for (i = 0; i < n; i++) {
542 v = index234(vertices, i);
543 j = v->vindex;
544
545 if (v->param >= MAXDEGREE)
546 break; /* nothing left to add! */
547
548 /*
549 * Sort the other vertices into order of their distance
550 * from this one. Don't bother looking below i, because
551 * we've already tried those edges the other way round.
552 * Also here we rule out target vertices with too high
553 * a degree, and (of course) ones to which we already
554 * have an edge.
555 */
556 m = 0;
557 for (k = i+1; k < n; k++) {
558 vertex *kv = index234(vertices, k);
559 int ki = kv->vindex;
560 int dx, dy;
561
562 if (kv->param >= MAXDEGREE || isedge(edges, ki, j))
563 continue;
564
565 vlist[m].vindex = ki;
566 dx = pts[ki].x - pts[j].x;
567 dy = pts[ki].y - pts[j].y;
568 vlist[m].param = dx*dx + dy*dy;
569 m++;
570 }
571
572 qsort(vlist, m, sizeof(*vlist), vertcmpC);
573
574 for (k = 0; k < m; k++) {
575 int p;
576 int ki = vlist[k].vindex;
577
578 /*
579 * Check to see whether this edge intersects any
580 * existing edge or point.
581 */
582 for (p = 0; p < n; p++)
583 if (p != ki && p != j && cross(pts[ki], pts[j],
584 pts[p], pts[p]))
585 break;
586 if (p < n)
587 continue;
588 for (p = 0; (e = index234(edges, p)) != NULL; p++)
589 if (e->a != ki && e->a != j &&
590 e->b != ki && e->b != j &&
591 cross(pts[ki], pts[j], pts[e->a], pts[e->b]))
592 break;
593 if (e)
594 continue;
595
596 /*
597 * We're done! Add this edge, modify the degrees of
598 * the two vertices involved, and break.
599 */
600 addedge(edges, j, ki);
601 added = TRUE;
602 del234(vertices, vs+j);
603 vs[j].param++;
604 add234(vertices, vs+j);
605 del234(vertices, vs+ki);
606 vs[ki].param++;
607 add234(vertices, vs+ki);
608 break;
609 }
610
611 if (k < m)
612 break;
613 }
614
615 if (!added)
616 break; /* we're done. */
617 }
618
619 /*
620 * That's our graph. Now shuffle the points, making sure that
621 * they come out with at least one crossed line when arranged
622 * in a circle (so that the puzzle isn't immediately solved!).
623 */
42159ec6 624 tmp = snewn(n, long);
9d6c3859 625 for (i = 0; i < n; i++)
626 tmp[i] = i;
627 pts2 = snewn(n, point);
628 make_circle(pts2, n, w);
629 while (1) {
630 shuffle(tmp, n, sizeof(*tmp), rs);
631 for (i = 0; (e = index234(edges, i)) != NULL; i++) {
632 for (j = i+1; (e2 = index234(edges, j)) != NULL; j++) {
633 if (e2->a == e->a || e2->a == e->b ||
634 e2->b == e->a || e2->b == e->b)
635 continue;
636 if (cross(pts2[tmp[e2->a]], pts2[tmp[e2->b]],
637 pts2[tmp[e->a]], pts2[tmp[e->b]]))
638 break;
639 }
640 if (e2)
641 break;
642 }
643 if (e)
644 break; /* we've found a crossing */
645 }
646
647 /*
648 * We're done. Now encode the graph in a string format. Let's
649 * use a comma-separated list of dash-separated vertex number
650 * pairs, numbered from zero. We'll sort the list to prevent
651 * side channels.
652 */
653 ret = NULL;
654 {
655 char *sep;
656 char buf[80];
657 int retlen;
658 edge *ea;
659
660 retlen = 0;
661 m = count234(edges);
662 ea = snewn(m, edge);
663 for (i = 0; (e = index234(edges, i)) != NULL; i++) {
664 assert(i < m);
665 ea[i].a = min(tmp[e->a], tmp[e->b]);
666 ea[i].b = max(tmp[e->a], tmp[e->b]);
667 retlen += 1 + sprintf(buf, "%d-%d", ea[i].a, ea[i].b);
668 }
669 assert(i == m);
670 qsort(ea, m, sizeof(*ea), edgecmpC);
671
672 ret = snewn(retlen, char);
673 sep = "";
674 k = 0;
675
676 for (i = 0; i < m; i++) {
677 k += sprintf(ret + k, "%s%d-%d", sep, ea[i].a, ea[i].b);
678 sep = ",";
679 }
680 assert(k < retlen);
681
682 sfree(ea);
683 }
684
685 /*
686 * Encode the solution we started with as an aux_info string.
687 */
688 {
689 char buf[80];
690 char *auxstr;
691 int auxlen;
692
693 auxlen = 2; /* leading 'S' and trailing '\0' */
694 for (i = 0; i < n; i++) {
695 j = tmp[i];
696 pts2[j] = pts[i];
697 if (pts2[j].d & 1) {
698 pts2[j].x *= 2;
699 pts2[j].y *= 2;
700 pts2[j].d *= 2;
701 }
702 pts2[j].x += pts2[j].d / 2;
703 pts2[j].y += pts2[j].d / 2;
42159ec6 704 auxlen += sprintf(buf, ";P%d:%ld,%ld/%ld", i,
9d6c3859 705 pts2[j].x, pts2[j].y, pts2[j].d);
706 }
707 k = 0;
708 auxstr = snewn(auxlen, char);
709 auxstr[k++] = 'S';
710 for (i = 0; i < n; i++)
42159ec6 711 k += sprintf(auxstr+k, ";P%d:%ld,%ld/%ld", i,
9d6c3859 712 pts2[i].x, pts2[i].y, pts2[i].d);
713 assert(k < auxlen);
714 *aux = auxstr;
715 }
716 sfree(pts2);
717
718 sfree(tmp);
719 sfree(vlist);
720 freetree234(vertices);
721 sfree(vs);
722 while ((e = delpos234(edges, 0)) != NULL)
723 sfree(e);
724 freetree234(edges);
725 sfree(pts);
726
727 return ret;
728}
729
730static char *validate_desc(game_params *params, char *desc)
731{
732 int a, b;
733
734 while (*desc) {
735 a = atoi(desc);
736 if (a < 0 || a >= params->n)
737 return "Number out of range in game description";
738 while (*desc && isdigit((unsigned char)*desc)) desc++;
739 if (*desc != '-')
740 return "Expected '-' after number in game description";
741 desc++; /* eat dash */
742 b = atoi(desc);
743 if (b < 0 || b >= params->n)
744 return "Number out of range in game description";
745 while (*desc && isdigit((unsigned char)*desc)) desc++;
746 if (*desc) {
747 if (*desc != ',')
748 return "Expected ',' after number in game description";
749 desc++; /* eat comma */
750 }
751 }
752
753 return NULL;
754}
755
0d98f76f 756static void mark_crossings(game_state *state)
757{
758 int ok = TRUE;
759 int i, j;
760 edge *e, *e2;
761
762#ifdef SHOW_CROSSINGS
763 for (i = 0; (e = index234(state->graph->edges, i)) != NULL; i++)
764 state->crosses[i] = FALSE;
765#endif
766
767 /*
768 * Check correctness: for every pair of edges, see whether they
769 * cross.
770 */
771 for (i = 0; (e = index234(state->graph->edges, i)) != NULL; i++) {
772 for (j = i+1; (e2 = index234(state->graph->edges, j)) != NULL; j++) {
773 if (e2->a == e->a || e2->a == e->b ||
774 e2->b == e->a || e2->b == e->b)
775 continue;
776 if (cross(state->pts[e2->a], state->pts[e2->b],
777 state->pts[e->a], state->pts[e->b])) {
778 ok = FALSE;
779#ifdef SHOW_CROSSINGS
780 state->crosses[i] = state->crosses[j] = TRUE;
781#else
782 goto done; /* multi-level break - sorry */
783#endif
784 }
785 }
786 }
787
788 /*
789 * e == NULL if we've gone through all the edge pairs
790 * without finding a crossing.
791 */
792#ifndef SHOW_CROSSINGS
793 done:
794#endif
795 if (ok)
796 state->completed = TRUE;
797}
798
dafd6cf6 799static game_state *new_game(midend *me, game_params *params, char *desc)
9d6c3859 800{
801 int n = params->n;
802 game_state *state = snew(game_state);
803 int a, b;
804
805 state->params = *params;
806 state->w = state->h = COORDLIMIT(n);
807 state->pts = snewn(n, point);
808 make_circle(state->pts, n, state->w);
809 state->graph = snew(struct graph);
810 state->graph->refcount = 1;
811 state->graph->edges = newtree234(edgecmp);
17c75e70 812 state->completed = state->cheated = state->just_solved = FALSE;
9d6c3859 813
814 while (*desc) {
815 a = atoi(desc);
816 assert(a >= 0 && a < params->n);
817 while (*desc && isdigit((unsigned char)*desc)) desc++;
818 assert(*desc == '-');
819 desc++; /* eat dash */
820 b = atoi(desc);
821 assert(b >= 0 && b < params->n);
822 while (*desc && isdigit((unsigned char)*desc)) desc++;
823 if (*desc) {
824 assert(*desc == ',');
825 desc++; /* eat comma */
826 }
827 addedge(state->graph->edges, a, b);
828 }
829
0d98f76f 830#ifdef SHOW_CROSSINGS
831 state->crosses = snewn(count234(state->graph->edges), int);
0d98f76f 832 mark_crossings(state); /* sets up `crosses' and `completed' */
17c75e70 833#endif
0d98f76f 834
9d6c3859 835 return state;
836}
837
838static game_state *dup_game(game_state *state)
839{
840 int n = state->params.n;
841 game_state *ret = snew(game_state);
842
843 ret->params = state->params;
844 ret->w = state->w;
845 ret->h = state->h;
846 ret->pts = snewn(n, point);
847 memcpy(ret->pts, state->pts, n * sizeof(point));
848 ret->graph = state->graph;
849 ret->graph->refcount++;
850 ret->completed = state->completed;
851 ret->cheated = state->cheated;
852 ret->just_solved = state->just_solved;
0d98f76f 853#ifdef SHOW_CROSSINGS
854 ret->crosses = snewn(count234(ret->graph->edges), int);
855 memcpy(ret->crosses, state->crosses,
856 count234(ret->graph->edges) * sizeof(int));
857#endif
9d6c3859 858
859 return ret;
860}
861
862static void free_game(game_state *state)
863{
864 if (--state->graph->refcount <= 0) {
865 edge *e;
866 while ((e = delpos234(state->graph->edges, 0)) != NULL)
867 sfree(e);
868 freetree234(state->graph->edges);
869 sfree(state->graph);
870 }
871 sfree(state->pts);
872 sfree(state);
873}
874
875static char *solve_game(game_state *state, game_state *currstate,
876 char *aux, char **error)
877{
886119cd 878 int n = state->params.n;
879 int matrix[4];
880 point *pts;
881 int i, j, besti;
882 float bestd;
883 char buf[80], *ret;
884 int retlen, retsize;
885
9d6c3859 886 if (!aux) {
887 *error = "Solution not known for this puzzle";
888 return NULL;
889 }
890
886119cd 891 /*
892 * Decode the aux_info to get the original point positions.
893 */
894 pts = snewn(n, point);
895 aux++; /* eat 'S' */
896 for (i = 0; i < n; i++) {
897 int p, k;
898 long x, y, d;
899 int ret = sscanf(aux, ";P%d:%ld,%ld/%ld%n", &p, &x, &y, &d, &k);
900 if (ret != 4 || p != i) {
901 *error = "Internal error: aux_info badly formatted";
902 sfree(pts);
903 return NULL;
904 }
905 pts[i].x = x;
906 pts[i].y = y;
907 pts[i].d = d;
908 aux += k;
909 }
910
911 /*
912 * Now go through eight possible symmetries of the point set.
913 * For each one, work out the sum of the Euclidean distances
914 * between the points' current positions and their new ones.
915 *
916 * We're squaring distances here, which means we're at risk of
917 * integer overflow. Fortunately, there's no real need to be
918 * massively careful about rounding errors, since this is a
919 * non-essential bit of the code; so I'll just work in floats
920 * internally.
921 */
922 besti = -1;
923 bestd = 0.0F;
924
925 for (i = 0; i < 8; i++) {
926 float d;
927
928 matrix[0] = matrix[1] = matrix[2] = matrix[3] = 0;
929 matrix[i & 1] = (i & 2) ? +1 : -1;
930 matrix[3-(i&1)] = (i & 4) ? +1 : -1;
931
932 d = 0.0F;
933 for (j = 0; j < n; j++) {
934 float px = (float)pts[j].x / pts[j].d;
935 float py = (float)pts[j].y / pts[j].d;
936 float sx = (float)currstate->pts[j].x / currstate->pts[j].d;
937 float sy = (float)currstate->pts[j].y / currstate->pts[j].d;
938 float cx = (float)currstate->w / 2;
939 float cy = (float)currstate->h / 2;
940 float ox, oy, dx, dy;
941
942 px -= cx;
943 py -= cy;
944
945 ox = matrix[0] * px + matrix[1] * py;
946 oy = matrix[2] * px + matrix[3] * py;
947
948 ox += cx;
949 oy += cy;
950
951 dx = ox - sx;
952 dy = oy - sy;
953
954 d += dx*dx + dy*dy;
955 }
956
957 if (besti < 0 || bestd > d) {
958 besti = i;
959 bestd = d;
960 }
961 }
962
963 assert(besti >= 0);
964
965 /*
966 * Now we know which symmetry is closest to the points' current
967 * positions. Use it.
968 */
969 matrix[0] = matrix[1] = matrix[2] = matrix[3] = 0;
970 matrix[besti & 1] = (besti & 2) ? +1 : -1;
971 matrix[3-(besti&1)] = (besti & 4) ? +1 : -1;
972
973 retsize = 256;
974 ret = snewn(retsize, char);
975 retlen = 0;
976 ret[retlen++] = 'S';
977 ret[retlen] = '\0';
978
979 for (i = 0; i < n; i++) {
980 float px = (float)pts[i].x / pts[i].d;
981 float py = (float)pts[i].y / pts[i].d;
982 float cx = (float)currstate->w / 2;
983 float cy = (float)currstate->h / 2;
984 float ox, oy;
985 int extra;
986
987 px -= cx;
988 py -= cy;
989
990 ox = matrix[0] * px + matrix[1] * py;
991 oy = matrix[2] * px + matrix[3] * py;
992
993 ox += cx;
994 oy += cy;
995
996 /*
997 * Use a fixed denominator of 2, because we know the
998 * original points were on an integer grid offset by 1/2.
999 */
1000 pts[i].d = 2;
1001 ox *= pts[i].d;
1002 oy *= pts[i].d;
5b502ae8 1003 pts[i].x = (long)(ox + 0.5F);
1004 pts[i].y = (long)(oy + 0.5F);
886119cd 1005
1006 extra = sprintf(buf, ";P%d:%ld,%ld/%ld", i,
1007 pts[i].x, pts[i].y, pts[i].d);
1008 if (retlen + extra >= retsize) {
1009 retsize = retlen + extra + 256;
1010 ret = sresize(ret, retsize, char);
1011 }
1012 strcpy(ret + retlen, buf);
1013 retlen += extra;
1014 }
1015
1016 sfree(pts);
1017
1018 return ret;
9d6c3859 1019}
1020
fa3abef5 1021static int game_can_format_as_text_now(game_params *params)
1022{
1023 return TRUE;
1024}
1025
9d6c3859 1026static char *game_text_format(game_state *state)
1027{
1028 return NULL;
1029}
1030
1031struct game_ui {
1032 int dragpoint; /* point being dragged; -1 if none */
1033 point newpoint; /* where it's been dragged to so far */
1034 int just_dragged; /* reset in game_changed_state */
1035 int just_moved; /* _set_ in game_changed_state */
1036 float anim_length;
1037};
1038
1039static game_ui *new_ui(game_state *state)
1040{
1041 game_ui *ui = snew(game_ui);
1042 ui->dragpoint = -1;
1043 ui->just_moved = ui->just_dragged = FALSE;
1044 return ui;
1045}
1046
1047static void free_ui(game_ui *ui)
1048{
1049 sfree(ui);
1050}
1051
1052static char *encode_ui(game_ui *ui)
1053{
1054 return NULL;
1055}
1056
1057static void decode_ui(game_ui *ui, char *encoding)
1058{
1059}
1060
1061static void game_changed_state(game_ui *ui, game_state *oldstate,
1062 game_state *newstate)
1063{
1064 ui->dragpoint = -1;
1065 ui->just_moved = ui->just_dragged;
1066 ui->just_dragged = FALSE;
1067}
1068
1069struct game_drawstate {
42159ec6 1070 long tilesize;
7dfe3b1f 1071 int bg, dragpoint;
1072 long *x, *y;
9d6c3859 1073};
1074
e1f3c707 1075static char *interpret_move(game_state *state, game_ui *ui, const game_drawstate *ds,
9d6c3859 1076 int x, int y, int button)
1077{
1078 int n = state->params.n;
1079
5b502ae8 1080 if (IS_MOUSE_DOWN(button)) {
42159ec6 1081 int i, best;
1082 long bestd;
9d6c3859 1083
1084 /*
1085 * Begin drag. We drag the vertex _nearest_ to the pointer,
1086 * just in case one is nearly on top of another and we want
1087 * to drag the latter. However, we drag nothing at all if
1088 * the nearest vertex is outside DRAG_THRESHOLD.
1089 */
1090 best = -1;
1091 bestd = 0;
1092
1093 for (i = 0; i < n; i++) {
42159ec6 1094 long px = state->pts[i].x * ds->tilesize / state->pts[i].d;
1095 long py = state->pts[i].y * ds->tilesize / state->pts[i].d;
1096 long dx = px - x;
1097 long dy = py - y;
1098 long d = dx*dx + dy*dy;
9d6c3859 1099
1100 if (best == -1 || bestd > d) {
1101 best = i;
1102 bestd = d;
1103 }
1104 }
1105
1106 if (bestd <= DRAG_THRESHOLD * DRAG_THRESHOLD) {
1107 ui->dragpoint = best;
1108 ui->newpoint.x = x;
1109 ui->newpoint.y = y;
1110 ui->newpoint.d = ds->tilesize;
1111 return "";
1112 }
1113
5b502ae8 1114 } else if (IS_MOUSE_DRAG(button) && ui->dragpoint >= 0) {
9d6c3859 1115 ui->newpoint.x = x;
1116 ui->newpoint.y = y;
1117 ui->newpoint.d = ds->tilesize;
1118 return "";
5b502ae8 1119 } else if (IS_MOUSE_RELEASE(button) && ui->dragpoint >= 0) {
9d6c3859 1120 int p = ui->dragpoint;
1121 char buf[80];
1122
1123 ui->dragpoint = -1; /* terminate drag, no matter what */
1124
1125 /*
1126 * First, see if we're within range. The user can cancel a
1127 * drag by dragging the point right off the window.
1128 */
42159ec6 1129 if (ui->newpoint.x < 0 ||
1130 ui->newpoint.x >= (long)state->w*ui->newpoint.d ||
1131 ui->newpoint.y < 0 ||
1132 ui->newpoint.y >= (long)state->h*ui->newpoint.d)
9d6c3859 1133 return "";
1134
1135 /*
1136 * We aren't cancelling the drag. Construct a move string
1137 * indicating where this point is going to.
1138 */
42159ec6 1139 sprintf(buf, "P%d:%ld,%ld/%ld", p,
9d6c3859 1140 ui->newpoint.x, ui->newpoint.y, ui->newpoint.d);
1141 ui->just_dragged = TRUE;
1142 return dupstr(buf);
1143 }
1144
1145 return NULL;
1146}
1147
1148static game_state *execute_move(game_state *state, char *move)
1149{
1150 int n = state->params.n;
42159ec6 1151 int p, k;
1152 long x, y, d;
9d6c3859 1153 game_state *ret = dup_game(state);
1154
1155 ret->just_solved = FALSE;
1156
1157 while (*move) {
1158 if (*move == 'S') {
1159 move++;
1160 if (*move == ';') move++;
1161 ret->cheated = ret->just_solved = TRUE;
1162 }
1163 if (*move == 'P' &&
42159ec6 1164 sscanf(move+1, "%d:%ld,%ld/%ld%n", &p, &x, &y, &d, &k) == 4 &&
9d6c3859 1165 p >= 0 && p < n && d > 0) {
1166 ret->pts[p].x = x;
1167 ret->pts[p].y = y;
1168 ret->pts[p].d = d;
1169
1170 move += k+1;
1171 if (*move == ';') move++;
1172 } else {
1173 free_game(ret);
1174 return NULL;
1175 }
1176 }
1177
0d98f76f 1178 mark_crossings(ret);
9d6c3859 1179
1180 return ret;
1181}
1182
1183/* ----------------------------------------------------------------------
1184 * Drawing routines.
1185 */
1186
1187static void game_compute_size(game_params *params, int tilesize,
1188 int *x, int *y)
1189{
1190 *x = *y = COORDLIMIT(params->n) * tilesize;
1191}
1192
dafd6cf6 1193static void game_set_size(drawing *dr, game_drawstate *ds,
1194 game_params *params, int tilesize)
9d6c3859 1195{
1196 ds->tilesize = tilesize;
1197}
1198
8266f3fc 1199static float *game_colours(frontend *fe, int *ncolours)
9d6c3859 1200{
1201 float *ret = snewn(3 * NCOLOURS, float);
1202
1203 frontend_default_colour(fe, &ret[COL_BACKGROUND * 3]);
1204
1205 ret[COL_LINE * 3 + 0] = 0.0F;
1206 ret[COL_LINE * 3 + 1] = 0.0F;
1207 ret[COL_LINE * 3 + 2] = 0.0F;
1208
0d98f76f 1209#ifdef SHOW_CROSSINGS
1210 ret[COL_CROSSEDLINE * 3 + 0] = 1.0F;
1211 ret[COL_CROSSEDLINE * 3 + 1] = 0.0F;
1212 ret[COL_CROSSEDLINE * 3 + 2] = 0.0F;
1213#endif
1214
9d6c3859 1215 ret[COL_OUTLINE * 3 + 0] = 0.0F;
1216 ret[COL_OUTLINE * 3 + 1] = 0.0F;
1217 ret[COL_OUTLINE * 3 + 2] = 0.0F;
1218
1219 ret[COL_POINT * 3 + 0] = 0.0F;
1220 ret[COL_POINT * 3 + 1] = 0.0F;
1221 ret[COL_POINT * 3 + 2] = 1.0F;
1222
1223 ret[COL_DRAGPOINT * 3 + 0] = 1.0F;
1224 ret[COL_DRAGPOINT * 3 + 1] = 1.0F;
1225 ret[COL_DRAGPOINT * 3 + 2] = 1.0F;
1226
1227 ret[COL_NEIGHBOUR * 3 + 0] = 1.0F;
1228 ret[COL_NEIGHBOUR * 3 + 1] = 0.0F;
1229 ret[COL_NEIGHBOUR * 3 + 2] = 0.0F;
1230
8eef6b92 1231 ret[COL_FLASH1 * 3 + 0] = 0.5F;
1232 ret[COL_FLASH1 * 3 + 1] = 0.5F;
1233 ret[COL_FLASH1 * 3 + 2] = 0.5F;
1234
1235 ret[COL_FLASH2 * 3 + 0] = 1.0F;
1236 ret[COL_FLASH2 * 3 + 1] = 1.0F;
1237 ret[COL_FLASH2 * 3 + 2] = 1.0F;
1238
9d6c3859 1239 *ncolours = NCOLOURS;
1240 return ret;
1241}
1242
dafd6cf6 1243static game_drawstate *game_new_drawstate(drawing *dr, game_state *state)
9d6c3859 1244{
1245 struct game_drawstate *ds = snew(struct game_drawstate);
7dfe3b1f 1246 int i;
9d6c3859 1247
1248 ds->tilesize = 0;
7dfe3b1f 1249 ds->x = snewn(state->params.n, long);
1250 ds->y = snewn(state->params.n, long);
1251 for (i = 0; i < state->params.n; i++)
1252 ds->x[i] = ds->y[i] = -1;
1253 ds->bg = -1;
1254 ds->dragpoint = -1;
9d6c3859 1255
1256 return ds;
1257}
1258
dafd6cf6 1259static void game_free_drawstate(drawing *dr, game_drawstate *ds)
9d6c3859 1260{
7dfe3b1f 1261 sfree(ds->y);
1262 sfree(ds->x);
9d6c3859 1263 sfree(ds);
1264}
1265
1266static point mix(point a, point b, float distance)
1267{
1268 point ret;
1269
1270 ret.d = a.d * b.d;
5b502ae8 1271 ret.x = (long)(a.x * b.d + distance * (b.x * a.d - a.x * b.d));
1272 ret.y = (long)(a.y * b.d + distance * (b.y * a.d - a.y * b.d));
9d6c3859 1273
1274 return ret;
1275}
1276
dafd6cf6 1277static void game_redraw(drawing *dr, game_drawstate *ds, game_state *oldstate,
9d6c3859 1278 game_state *state, int dir, game_ui *ui,
1279 float animtime, float flashtime)
1280{
1281 int w, h;
1282 edge *e;
1283 int i, j;
7dfe3b1f 1284 int bg, points_moved;
9d6c3859 1285
1286 /*
1287 * There's no terribly sensible way to do partial redraws of
1288 * this game, so I'm going to have to resort to redrawing the
1289 * whole thing every time.
1290 */
1291
8eef6b92 1292 if (flashtime == 0)
1293 bg = COL_BACKGROUND;
1294 else if ((int)(flashtime * 4 / FLASH_TIME) % 2 == 0)
1295 bg = COL_FLASH1;
1296 else
1297 bg = COL_FLASH2;
1298
7dfe3b1f 1299 /*
1300 * To prevent excessive spinning on redraw during a completion
1301 * flash, we first check to see if _either_ the flash
1302 * background colour has changed _or_ at least one point has
1303 * moved _or_ a drag has begun or ended, and abandon the redraw
1304 * if neither is the case.
1305 *
1306 * Also in this loop we work out the coordinates of all the
1307 * points for this redraw.
1308 */
1309 points_moved = FALSE;
1310 for (i = 0; i < state->params.n; i++) {
1311 point p = state->pts[i];
1312 long x, y;
1313
1314 if (ui->dragpoint == i)
1315 p = ui->newpoint;
1316
1317 if (oldstate)
1318 p = mix(oldstate->pts[i], p, animtime / ui->anim_length);
1319
1320 x = p.x * ds->tilesize / p.d;
1321 y = p.y * ds->tilesize / p.d;
1322
1323 if (ds->x[i] != x || ds->y[i] != y)
1324 points_moved = TRUE;
1325
1326 ds->x[i] = x;
1327 ds->y[i] = y;
1328 }
1329
1330 if (ds->bg == bg && ds->dragpoint == ui->dragpoint && !points_moved)
1331 return; /* nothing to do */
1332
1333 ds->dragpoint = ui->dragpoint;
1334 ds->bg = bg;
1335
9d6c3859 1336 game_compute_size(&state->params, ds->tilesize, &w, &h);
dafd6cf6 1337 draw_rect(dr, 0, 0, w, h, bg);
9d6c3859 1338
1339 /*
1340 * Draw the edges.
1341 */
1342
1343 for (i = 0; (e = index234(state->graph->edges, i)) != NULL; i++) {
dafd6cf6 1344 draw_line(dr, ds->x[e->a], ds->y[e->a], ds->x[e->b], ds->y[e->b],
0d98f76f 1345#ifdef SHOW_CROSSINGS
1346 (oldstate?oldstate:state)->crosses[i] ?
1347 COL_CROSSEDLINE :
1348#endif
1349 COL_LINE);
9d6c3859 1350 }
1351
1352 /*
1353 * Draw the points.
1354 *
1355 * When dragging, we should not only vary the colours, but
1356 * leave the point being dragged until last.
1357 */
1358 for (j = 0; j < 3; j++) {
1359 int thisc = (j == 0 ? COL_POINT :
1360 j == 1 ? COL_NEIGHBOUR : COL_DRAGPOINT);
1361 for (i = 0; i < state->params.n; i++) {
42159ec6 1362 int c;
9d6c3859 1363
1364 if (ui->dragpoint == i) {
9d6c3859 1365 c = COL_DRAGPOINT;
1366 } else if (ui->dragpoint >= 0 &&
1367 isedge(state->graph->edges, ui->dragpoint, i)) {
1368 c = COL_NEIGHBOUR;
1369 } else {
1370 c = COL_POINT;
1371 }
1372
9d6c3859 1373 if (c == thisc) {
9d6c3859 1374#ifdef VERTEX_NUMBERS
dafd6cf6 1375 draw_circle(dr, ds->x[i], ds->y[i], DRAG_THRESHOLD, bg, bg);
9d6c3859 1376 {
1377 char buf[80];
1378 sprintf(buf, "%d", i);
dafd6cf6 1379 draw_text(dr, ds->x[i], ds->y[i], FONT_VARIABLE,
7dfe3b1f 1380 DRAG_THRESHOLD*3/2,
9d6c3859 1381 ALIGN_VCENTRE|ALIGN_HCENTRE, c, buf);
1382 }
1383#else
dafd6cf6 1384 draw_circle(dr, ds->x[i], ds->y[i], CIRCLE_RADIUS,
7dfe3b1f 1385 c, COL_OUTLINE);
9d6c3859 1386#endif
1387 }
1388 }
1389 }
1390
dafd6cf6 1391 draw_update(dr, 0, 0, w, h);
9d6c3859 1392}
1393
1394static float game_anim_length(game_state *oldstate, game_state *newstate,
1395 int dir, game_ui *ui)
1396{
1397 if (ui->just_moved)
1398 return 0.0F;
1399 if ((dir < 0 ? oldstate : newstate)->just_solved)
1400 ui->anim_length = SOLVEANIM_TIME;
1401 else
1402 ui->anim_length = ANIM_TIME;
1403 return ui->anim_length;
1404}
1405
1406static float game_flash_length(game_state *oldstate, game_state *newstate,
1407 int dir, game_ui *ui)
1408{
1409 if (!oldstate->completed && newstate->completed &&
1410 !oldstate->cheated && !newstate->cheated)
1411 return FLASH_TIME;
1412 return 0.0F;
1413}
1414
1cea529f 1415static int game_status(game_state *state)
4496362f 1416{
1cea529f 1417 return state->completed ? +1 : 0;
4496362f 1418}
1419
9d6c3859 1420static int game_timing_state(game_state *state, game_ui *ui)
1421{
1422 return TRUE;
1423}
1424
dafd6cf6 1425static void game_print_size(game_params *params, float *x, float *y)
1426{
1427}
1428
1429static void game_print(drawing *dr, game_state *state, int tilesize)
1430{
1431}
1432
9d6c3859 1433#ifdef COMBINED
1434#define thegame untangle
1435#endif
1436
1437const struct game thegame = {
750037d7 1438 "Untangle", "games.untangle", "untangle",
9d6c3859 1439 default_params,
1440 game_fetch_preset,
1441 decode_params,
1442 encode_params,
1443 free_params,
1444 dup_params,
1445 TRUE, game_configure, custom_params,
1446 validate_params,
1447 new_game_desc,
1448 validate_desc,
1449 new_game,
1450 dup_game,
1451 free_game,
1452 TRUE, solve_game,
fa3abef5 1453 FALSE, game_can_format_as_text_now, game_text_format,
9d6c3859 1454 new_ui,
1455 free_ui,
1456 encode_ui,
1457 decode_ui,
1458 game_changed_state,
1459 interpret_move,
1460 execute_move,
1461 PREFERRED_TILESIZE, game_compute_size, game_set_size,
1462 game_colours,
1463 game_new_drawstate,
1464 game_free_drawstate,
1465 game_redraw,
1466 game_anim_length,
1467 game_flash_length,
1cea529f 1468 game_status,
dafd6cf6 1469 FALSE, FALSE, game_print_size, game_print,
ac9f41c4 1470 FALSE, /* wants_statusbar */
9d6c3859 1471 FALSE, game_timing_state,
2705d374 1472 SOLVE_ANIMATES, /* flags */
9d6c3859 1473};