14 #define MAXVERTICES 20
19 float vertices
[MAXVERTICES
* 3]; /* 3*npoints coordinates */
22 int faces
[MAXFACES
* MAXORDER
]; /* order*nfaces point indices */
23 float normals
[MAXFACES
* 3]; /* 3*npoints vector components */
24 float shear
; /* isometric shear for nice drawing */
25 float border
; /* border required around arena */
28 static const struct solid s_tetrahedron
= {
31 0.0F
, -0.57735026919F
, -0.20412414523F
,
32 -0.5F
, 0.28867513459F
, -0.20412414523F
,
33 0.0F
, -0.0F
, 0.6123724357F
,
34 0.5F
, 0.28867513459F
, -0.20412414523F
,
38 0,2,1, 3,1,2, 2,0,3, 1,3,0
41 -0.816496580928F
, -0.471404520791F
, 0.333333333334F
,
42 0.0F
, 0.942809041583F
, 0.333333333333F
,
43 0.816496580928F
, -0.471404520791F
, 0.333333333334F
,
49 static const struct solid s_cube
= {
52 -0.5F
,-0.5F
,-0.5F
, -0.5F
,-0.5F
,+0.5F
,
53 -0.5F
,+0.5F
,-0.5F
, -0.5F
,+0.5F
,+0.5F
,
54 +0.5F
,-0.5F
,-0.5F
, +0.5F
,-0.5F
,+0.5F
,
55 +0.5F
,+0.5F
,-0.5F
, +0.5F
,+0.5F
,+0.5F
,
59 0,1,3,2, 1,5,7,3, 5,4,6,7, 4,0,2,6, 0,4,5,1, 3,7,6,2
62 -1.0F
,0.0F
,0.0F
, 0.0F
,0.0F
,+1.0F
,
63 +1.0F
,0.0F
,0.0F
, 0.0F
,0.0F
,-1.0F
,
64 0.0F
,-1.0F
,0.0F
, 0.0F
,+1.0F
,0.0F
69 static const struct solid s_octahedron
= {
72 -0.5F
, -0.28867513459472505F
, 0.4082482904638664F
,
73 0.5F
, 0.28867513459472505F
, -0.4082482904638664F
,
74 -0.5F
, 0.28867513459472505F
, -0.4082482904638664F
,
75 0.5F
, -0.28867513459472505F
, 0.4082482904638664F
,
76 0.0F
, -0.57735026918945009F
, -0.4082482904638664F
,
77 0.0F
, 0.57735026918945009F
, 0.4082482904638664F
,
81 4,0,2, 0,5,2, 0,4,3, 5,0,3, 1,4,2, 5,1,2, 4,1,3, 1,5,3
84 -0.816496580928F
, -0.471404520791F
, -0.333333333334F
,
85 -0.816496580928F
, 0.471404520791F
, 0.333333333334F
,
86 0.0F
, -0.942809041583F
, 0.333333333333F
,
89 0.0F
, 0.942809041583F
, -0.333333333333F
,
90 0.816496580928F
, -0.471404520791F
, -0.333333333334F
,
91 0.816496580928F
, 0.471404520791F
, 0.333333333334F
,
96 static const struct solid s_icosahedron
= {
99 0.0F
, 0.57735026919F
, 0.75576131408F
,
100 0.0F
, -0.93417235896F
, 0.17841104489F
,
101 0.0F
, 0.93417235896F
, -0.17841104489F
,
102 0.0F
, -0.57735026919F
, -0.75576131408F
,
103 -0.5F
, -0.28867513459F
, 0.75576131408F
,
104 -0.5F
, 0.28867513459F
, -0.75576131408F
,
105 0.5F
, -0.28867513459F
, 0.75576131408F
,
106 0.5F
, 0.28867513459F
, -0.75576131408F
,
107 -0.80901699437F
, 0.46708617948F
, 0.17841104489F
,
108 0.80901699437F
, 0.46708617948F
, 0.17841104489F
,
109 -0.80901699437F
, -0.46708617948F
, -0.17841104489F
,
110 0.80901699437F
, -0.46708617948F
, -0.17841104489F
,
114 8,0,2, 0,9,2, 1,10,3, 11,1,3, 0,4,6,
115 4,1,6, 5,2,7, 3,5,7, 4,8,10, 8,5,10,
116 9,6,11, 7,9,11, 0,8,4, 9,0,6, 10,1,4,
117 1,11,6, 8,2,5, 2,9,7, 3,10,5, 11,3,7,
120 -0.356822089773F
, 0.87267799625F
, 0.333333333333F
,
121 0.356822089773F
, 0.87267799625F
, 0.333333333333F
,
122 -0.356822089773F
, -0.87267799625F
, -0.333333333333F
,
123 0.356822089773F
, -0.87267799625F
, -0.333333333333F
,
125 0.0F
, -0.666666666667F
, 0.745355992501F
,
126 0.0F
, 0.666666666667F
, -0.745355992501F
,
128 -0.934172358963F
, -0.12732200375F
, 0.333333333333F
,
129 -0.934172358963F
, 0.12732200375F
, -0.333333333333F
,
130 0.934172358963F
, -0.12732200375F
, 0.333333333333F
,
131 0.934172358963F
, 0.12732200375F
, -0.333333333333F
,
132 -0.57735026919F
, 0.333333333334F
, 0.745355992501F
,
133 0.57735026919F
, 0.333333333334F
, 0.745355992501F
,
134 -0.57735026919F
, -0.745355992501F
, 0.333333333334F
,
135 0.57735026919F
, -0.745355992501F
, 0.333333333334F
,
136 -0.57735026919F
, 0.745355992501F
, -0.333333333334F
,
137 0.57735026919F
, 0.745355992501F
, -0.333333333334F
,
138 -0.57735026919F
, -0.333333333334F
, -0.745355992501F
,
139 0.57735026919F
, -0.333333333334F
, -0.745355992501F
,
145 TETRAHEDRON
, CUBE
, OCTAHEDRON
, ICOSAHEDRON
147 static const struct solid
*solids
[] = {
148 &s_tetrahedron
, &s_cube
, &s_octahedron
, &s_icosahedron
158 enum { LEFT
, RIGHT
, UP
, DOWN
, UP_LEFT
, UP_RIGHT
, DOWN_LEFT
, DOWN_RIGHT
};
160 #define GRID_SCALE 48.0F
161 #define ROLLTIME 0.13F
163 #define SQ(x) ( (x) * (x) )
165 #define MATMUL(ra,m,a) do { \
166 float rx, ry, rz, xx = (a)[0], yy = (a)[1], zz = (a)[2], *mat = (m); \
167 rx = mat[0] * xx + mat[3] * yy + mat[6] * zz; \
168 ry = mat[1] * xx + mat[4] * yy + mat[7] * zz; \
169 rz = mat[2] * xx + mat[5] * yy + mat[8] * zz; \
170 (ra)[0] = rx; (ra)[1] = ry; (ra)[2] = rz; \
173 #define APPROXEQ(x,y) ( SQ(x-y) < 0.1 )
178 float points
[8]; /* maximum */
179 int directions
[8]; /* bit masks showing point pairs */
188 * Grid dimensions. For a square grid these are width and
189 * height respectively; otherwise the grid is a hexagon, with
190 * the top side and the two lower diagonals having length d1
191 * and the remaining three sides having length d2 (so that
192 * d1==d2 gives a regular hexagon, and d2==0 gives a triangle).
198 struct game_params params
;
199 const struct solid
*solid
;
201 struct grid_square
*squares
;
203 int current
; /* index of current grid square */
204 int sgkey
[2]; /* key-point indices into grid sq */
205 int dgkey
[2]; /* key-point indices into grid sq */
206 int spkey
[2]; /* key-point indices into polyhedron */
207 int dpkey
[2]; /* key-point indices into polyhedron */
214 static game_params
*default_params(void)
216 game_params
*ret
= snew(game_params
);
225 static int game_fetch_preset(int i
, char **name
, game_params
**params
)
227 game_params
*ret
= snew(game_params
);
239 ret
->solid
= TETRAHEDRON
;
245 ret
->solid
= OCTAHEDRON
;
251 ret
->solid
= ICOSAHEDRON
;
265 static void free_params(game_params
*params
)
270 static game_params
*dup_params(game_params
*params
)
272 game_params
*ret
= snew(game_params
);
273 *ret
= *params
; /* structure copy */
277 static void decode_params(game_params
*ret
, char const *string
)
280 case 't': ret
->solid
= TETRAHEDRON
; string
++; break;
281 case 'c': ret
->solid
= CUBE
; string
++; break;
282 case 'o': ret
->solid
= OCTAHEDRON
; string
++; break;
283 case 'i': ret
->solid
= ICOSAHEDRON
; string
++; break;
286 ret
->d1
= ret
->d2
= atoi(string
);
287 while (*string
&& isdigit(*string
)) string
++;
288 if (*string
== 'x') {
290 ret
->d2
= atoi(string
);
294 static char *encode_params(game_params
*params
, int full
)
298 assert(params
->solid
>= 0 && params
->solid
< 4);
299 sprintf(data
, "%c%dx%d", "tcoi"[params
->solid
], params
->d1
, params
->d2
);
304 static void enum_grid_squares(game_params
*params
,
305 void (*callback
)(void *, struct grid_square
*),
308 const struct solid
*solid
= solids
[params
->solid
];
310 if (solid
->order
== 4) {
313 for (y
= 0; y
< params
->d2
; y
++)
314 for (x
= 0; x
< params
->d1
; x
++) {
315 struct grid_square sq
;
319 sq
.points
[0] = x
- 0.5F
;
320 sq
.points
[1] = y
- 0.5F
;
321 sq
.points
[2] = x
- 0.5F
;
322 sq
.points
[3] = y
+ 0.5F
;
323 sq
.points
[4] = x
+ 0.5F
;
324 sq
.points
[5] = y
+ 0.5F
;
325 sq
.points
[6] = x
+ 0.5F
;
326 sq
.points
[7] = y
- 0.5F
;
329 sq
.directions
[LEFT
] = 0x03; /* 0,1 */
330 sq
.directions
[RIGHT
] = 0x0C; /* 2,3 */
331 sq
.directions
[UP
] = 0x09; /* 0,3 */
332 sq
.directions
[DOWN
] = 0x06; /* 1,2 */
333 sq
.directions
[UP_LEFT
] = 0; /* no diagonals in a square */
334 sq
.directions
[UP_RIGHT
] = 0; /* no diagonals in a square */
335 sq
.directions
[DOWN_LEFT
] = 0; /* no diagonals in a square */
336 sq
.directions
[DOWN_RIGHT
] = 0; /* no diagonals in a square */
341 * This is supremely irrelevant, but just to avoid
342 * having any uninitialised structure members...
349 int row
, rowlen
, other
, i
, firstix
= -1;
350 float theight
= (float)(sqrt(3) / 2.0);
352 for (row
= 0; row
< params
->d1
+ params
->d2
; row
++) {
353 if (row
< params
->d2
) {
355 rowlen
= row
+ params
->d1
;
358 rowlen
= 2*params
->d2
+ params
->d1
- row
;
362 * There are `rowlen' down-pointing triangles.
364 for (i
= 0; i
< rowlen
; i
++) {
365 struct grid_square sq
;
369 ix
= (2 * i
- (rowlen
-1));
373 sq
.y
= y
+ theight
/ 3;
374 sq
.points
[0] = x
- 0.5F
;
377 sq
.points
[3] = y
+ theight
;
378 sq
.points
[4] = x
+ 0.5F
;
382 sq
.directions
[LEFT
] = 0x03; /* 0,1 */
383 sq
.directions
[RIGHT
] = 0x06; /* 1,2 */
384 sq
.directions
[UP
] = 0x05; /* 0,2 */
385 sq
.directions
[DOWN
] = 0; /* invalid move */
388 * Down-pointing triangle: both the up diagonals go
389 * up, and the down ones go left and right.
391 sq
.directions
[UP_LEFT
] = sq
.directions
[UP_RIGHT
] =
393 sq
.directions
[DOWN_LEFT
] = sq
.directions
[LEFT
];
394 sq
.directions
[DOWN_RIGHT
] = sq
.directions
[RIGHT
];
401 sq
.tetra_class
= ((row
+(ix
&1)) & 2) ^ (ix
& 3);
407 * There are `rowlen+other' up-pointing triangles.
409 for (i
= 0; i
< rowlen
+other
; i
++) {
410 struct grid_square sq
;
414 ix
= (2 * i
- (rowlen
+other
-1));
418 sq
.y
= y
+ 2*theight
/ 3;
419 sq
.points
[0] = x
+ 0.5F
;
420 sq
.points
[1] = y
+ theight
;
423 sq
.points
[4] = x
- 0.5F
;
424 sq
.points
[5] = y
+ theight
;
427 sq
.directions
[LEFT
] = 0x06; /* 1,2 */
428 sq
.directions
[RIGHT
] = 0x03; /* 0,1 */
429 sq
.directions
[DOWN
] = 0x05; /* 0,2 */
430 sq
.directions
[UP
] = 0; /* invalid move */
433 * Up-pointing triangle: both the down diagonals go
434 * down, and the up ones go left and right.
436 sq
.directions
[DOWN_LEFT
] = sq
.directions
[DOWN_RIGHT
] =
438 sq
.directions
[UP_LEFT
] = sq
.directions
[LEFT
];
439 sq
.directions
[UP_RIGHT
] = sq
.directions
[RIGHT
];
444 firstix
= (ix
- 1) & 3;
446 sq
.tetra_class
= ((row
+(ix
&1)) & 2) ^ (ix
& 3);
454 static int grid_area(int d1
, int d2
, int order
)
457 * An NxM grid of squares has NM squares in it.
459 * A grid of triangles with dimensions A and B has a total of
460 * A^2 + B^2 + 4AB triangles in it. (You can divide it up into
461 * a side-A triangle containing A^2 subtriangles, a side-B
462 * triangle containing B^2, and two congruent parallelograms,
463 * each with side lengths A and B, each therefore containing AB
464 * two-triangle rhombuses.)
469 return d1
*d1
+ d2
*d2
+ 4*d1
*d2
;
472 static config_item
*game_configure(game_params
*params
)
474 config_item
*ret
= snewn(4, config_item
);
477 ret
[0].name
= "Type of solid";
478 ret
[0].type
= C_CHOICES
;
479 ret
[0].sval
= ":Tetrahedron:Cube:Octahedron:Icosahedron";
480 ret
[0].ival
= params
->solid
;
482 ret
[1].name
= "Width / top";
483 ret
[1].type
= C_STRING
;
484 sprintf(buf
, "%d", params
->d1
);
485 ret
[1].sval
= dupstr(buf
);
488 ret
[2].name
= "Height / bottom";
489 ret
[2].type
= C_STRING
;
490 sprintf(buf
, "%d", params
->d2
);
491 ret
[2].sval
= dupstr(buf
);
502 static game_params
*custom_params(config_item
*cfg
)
504 game_params
*ret
= snew(game_params
);
506 ret
->solid
= cfg
[0].ival
;
507 ret
->d1
= atoi(cfg
[1].sval
);
508 ret
->d2
= atoi(cfg
[2].sval
);
513 static void count_grid_square_callback(void *ctx
, struct grid_square
*sq
)
515 int *classes
= (int *)ctx
;
519 thisclass
= sq
->tetra_class
;
520 else if (classes
[4] == 2)
521 thisclass
= sq
->flip
;
525 classes
[thisclass
]++;
528 static char *validate_params(game_params
*params
)
533 if (params
->solid
< 0 || params
->solid
>= lenof(solids
))
534 return "Unrecognised solid type";
536 if (solids
[params
->solid
]->order
== 4) {
537 if (params
->d1
<= 0 || params
->d2
<= 0)
538 return "Both grid dimensions must be greater than zero";
540 if (params
->d1
<= 0 && params
->d2
<= 0)
541 return "At least one grid dimension must be greater than zero";
544 for (i
= 0; i
< 4; i
++)
546 if (params
->solid
== TETRAHEDRON
)
548 else if (params
->solid
== OCTAHEDRON
)
552 enum_grid_squares(params
, count_grid_square_callback
, classes
);
554 for (i
= 0; i
< classes
[4]; i
++)
555 if (classes
[i
] < solids
[params
->solid
]->nfaces
/ classes
[4])
556 return "Not enough grid space to place all blue faces";
558 if (grid_area(params
->d1
, params
->d2
, solids
[params
->solid
]->order
) <
559 solids
[params
->solid
]->nfaces
+ 1)
560 return "Not enough space to place the solid on an empty square";
572 static void classify_grid_square_callback(void *ctx
, struct grid_square
*sq
)
574 struct grid_data
*data
= (struct grid_data
*)ctx
;
577 if (data
->nclasses
== 4)
578 thisclass
= sq
->tetra_class
;
579 else if (data
->nclasses
== 2)
580 thisclass
= sq
->flip
;
584 data
->gridptrs
[thisclass
][data
->nsquares
[thisclass
]++] =
588 static char *new_game_desc(game_params
*params
, random_state
*rs
,
589 game_aux_info
**aux
, int interactive
)
591 struct grid_data data
;
592 int i
, j
, k
, m
, area
, facesperclass
;
597 * Enumerate the grid squares, dividing them into equivalence
598 * classes as appropriate. (For the tetrahedron, there is one
599 * equivalence class for each face; for the octahedron there
600 * are two classes; for the other two solids there's only one.)
603 area
= grid_area(params
->d1
, params
->d2
, solids
[params
->solid
]->order
);
604 if (params
->solid
== TETRAHEDRON
)
606 else if (params
->solid
== OCTAHEDRON
)
610 data
.gridptrs
[0] = snewn(data
.nclasses
* area
, int);
611 for (i
= 0; i
< data
.nclasses
; i
++) {
612 data
.gridptrs
[i
] = data
.gridptrs
[0] + i
* area
;
613 data
.nsquares
[i
] = 0;
615 data
.squareindex
= 0;
616 enum_grid_squares(params
, classify_grid_square_callback
, &data
);
618 facesperclass
= solids
[params
->solid
]->nfaces
/ data
.nclasses
;
620 for (i
= 0; i
< data
.nclasses
; i
++)
621 assert(data
.nsquares
[i
] >= facesperclass
);
622 assert(data
.squareindex
== area
);
625 * So now we know how many faces to allocate in each class. Get
628 flags
= snewn(area
, int);
629 for (i
= 0; i
< area
; i
++)
632 for (i
= 0; i
< data
.nclasses
; i
++) {
633 for (j
= 0; j
< facesperclass
; j
++) {
634 int n
= random_upto(rs
, data
.nsquares
[i
]);
636 assert(!flags
[data
.gridptrs
[i
][n
]]);
637 flags
[data
.gridptrs
[i
][n
]] = TRUE
;
640 * Move everything else up the array. I ought to use a
641 * better data structure for this, but for such small
642 * numbers it hardly seems worth the effort.
644 while (n
< data
.nsquares
[i
]-1) {
645 data
.gridptrs
[i
][n
] = data
.gridptrs
[i
][n
+1];
653 * Now we know precisely which squares are blue. Encode this
654 * information in hex. While we're looping over this, collect
655 * the non-blue squares into a list in the now-unused gridptrs
658 desc
= snewn(area
/ 4 + 40, char);
663 for (i
= 0; i
< area
; i
++) {
667 data
.gridptrs
[0][m
++] = i
;
671 *p
++ = "0123456789ABCDEF"[j
];
677 *p
++ = "0123456789ABCDEF"[j
];
680 * Choose a non-blue square for the polyhedron.
682 sprintf(p
, ",%d", data
.gridptrs
[0][random_upto(rs
, m
)]);
684 sfree(data
.gridptrs
[0]);
690 static void game_free_aux_info(game_aux_info
*aux
)
692 assert(!"Shouldn't happen");
695 static void add_grid_square_callback(void *ctx
, struct grid_square
*sq
)
697 game_state
*state
= (game_state
*)ctx
;
699 state
->squares
[state
->nsquares
] = *sq
; /* structure copy */
700 state
->squares
[state
->nsquares
].blue
= FALSE
;
704 static int lowest_face(const struct solid
*solid
)
711 for (i
= 0; i
< solid
->nfaces
; i
++) {
714 for (j
= 0; j
< solid
->order
; j
++) {
715 int f
= solid
->faces
[i
*solid
->order
+ j
];
716 z
+= solid
->vertices
[f
*3+2];
719 if (i
== 0 || zmin
> z
) {
728 static int align_poly(const struct solid
*solid
, struct grid_square
*sq
,
733 int flip
= (sq
->flip ?
-1 : +1);
736 * First, find the lowest z-coordinate present in the solid.
739 for (i
= 0; i
< solid
->nvertices
; i
++)
740 if (zmin
> solid
->vertices
[i
*3+2])
741 zmin
= solid
->vertices
[i
*3+2];
744 * Now go round the grid square. For each point in the grid
745 * square, we're looking for a point of the polyhedron with the
746 * same x- and y-coordinates (relative to the square's centre),
747 * and z-coordinate equal to zmin (near enough).
749 for (j
= 0; j
< sq
->npoints
; j
++) {
755 for (i
= 0; i
< solid
->nvertices
; i
++) {
758 dist
+= SQ(solid
->vertices
[i
*3+0] * flip
- sq
->points
[j
*2+0] + sq
->x
);
759 dist
+= SQ(solid
->vertices
[i
*3+1] * flip
- sq
->points
[j
*2+1] + sq
->y
);
760 dist
+= SQ(solid
->vertices
[i
*3+2] - zmin
);
768 if (matches
!= 1 || index
< 0)
776 static void flip_poly(struct solid
*solid
, int flip
)
781 for (i
= 0; i
< solid
->nvertices
; i
++) {
782 solid
->vertices
[i
*3+0] *= -1;
783 solid
->vertices
[i
*3+1] *= -1;
785 for (i
= 0; i
< solid
->nfaces
; i
++) {
786 solid
->normals
[i
*3+0] *= -1;
787 solid
->normals
[i
*3+1] *= -1;
792 static struct solid
*transform_poly(const struct solid
*solid
, int flip
,
793 int key0
, int key1
, float angle
)
795 struct solid
*ret
= snew(struct solid
);
796 float vx
, vy
, ax
, ay
;
797 float vmatrix
[9], amatrix
[9], vmatrix2
[9];
800 *ret
= *solid
; /* structure copy */
802 flip_poly(ret
, flip
);
805 * Now rotate the polyhedron through the given angle. We must
806 * rotate about the Z-axis to bring the two vertices key0 and
807 * key1 into horizontal alignment, then rotate about the
808 * X-axis, then rotate back again.
810 vx
= ret
->vertices
[key1
*3+0] - ret
->vertices
[key0
*3+0];
811 vy
= ret
->vertices
[key1
*3+1] - ret
->vertices
[key0
*3+1];
812 assert(APPROXEQ(vx
*vx
+ vy
*vy
, 1.0));
814 vmatrix
[0] = vx
; vmatrix
[3] = vy
; vmatrix
[6] = 0;
815 vmatrix
[1] = -vy
; vmatrix
[4] = vx
; vmatrix
[7] = 0;
816 vmatrix
[2] = 0; vmatrix
[5] = 0; vmatrix
[8] = 1;
818 ax
= (float)cos(angle
);
819 ay
= (float)sin(angle
);
821 amatrix
[0] = 1; amatrix
[3] = 0; amatrix
[6] = 0;
822 amatrix
[1] = 0; amatrix
[4] = ax
; amatrix
[7] = ay
;
823 amatrix
[2] = 0; amatrix
[5] = -ay
; amatrix
[8] = ax
;
825 memcpy(vmatrix2
, vmatrix
, sizeof(vmatrix
));
829 for (i
= 0; i
< ret
->nvertices
; i
++) {
830 MATMUL(ret
->vertices
+ 3*i
, vmatrix
, ret
->vertices
+ 3*i
);
831 MATMUL(ret
->vertices
+ 3*i
, amatrix
, ret
->vertices
+ 3*i
);
832 MATMUL(ret
->vertices
+ 3*i
, vmatrix2
, ret
->vertices
+ 3*i
);
834 for (i
= 0; i
< ret
->nfaces
; i
++) {
835 MATMUL(ret
->normals
+ 3*i
, vmatrix
, ret
->normals
+ 3*i
);
836 MATMUL(ret
->normals
+ 3*i
, amatrix
, ret
->normals
+ 3*i
);
837 MATMUL(ret
->normals
+ 3*i
, vmatrix2
, ret
->normals
+ 3*i
);
843 static char *validate_desc(game_params
*params
, char *desc
)
845 int area
= grid_area(params
->d1
, params
->d2
, solids
[params
->solid
]->order
);
849 for (j
= 0; j
< i
; j
++) {
851 if (c
>= '0' && c
<= '9') continue;
852 if (c
>= 'A' && c
<= 'F') continue;
853 if (c
>= 'a' && c
<= 'f') continue;
854 return "Not enough hex digits at start of string";
855 /* NB if desc[j]=='\0' that will also be caught here, so we're safe */
859 return "Expected ',' after hex digits";
863 if (desc
[i
] < '0' || desc
[i
] > '9')
864 return "Expected decimal integer after ','";
871 static game_state
*new_game(midend_data
*me
, game_params
*params
, char *desc
)
873 game_state
*state
= snew(game_state
);
876 state
->params
= *params
; /* structure copy */
877 state
->solid
= solids
[params
->solid
];
879 area
= grid_area(params
->d1
, params
->d2
, state
->solid
->order
);
880 state
->squares
= snewn(area
, struct grid_square
);
882 enum_grid_squares(params
, add_grid_square_callback
, state
);
883 assert(state
->nsquares
== area
);
885 state
->facecolours
= snewn(state
->solid
->nfaces
, int);
886 memset(state
->facecolours
, 0, state
->solid
->nfaces
* sizeof(int));
889 * Set up the blue squares and polyhedron position according to
890 * the game description.
898 for (i
= 0; i
< state
->nsquares
; i
++) {
901 if (v
>= '0' && v
<= '9')
903 else if (v
>= 'A' && v
<= 'F')
905 else if (v
>= 'a' && v
<= 'f')
911 state
->squares
[i
].blue
= TRUE
;
920 state
->current
= atoi(p
);
921 if (state
->current
< 0 || state
->current
>= state
->nsquares
)
922 state
->current
= 0; /* got to do _something_ */
926 * Align the polyhedron with its grid square and determine
927 * initial key points.
933 ret
= align_poly(state
->solid
, &state
->squares
[state
->current
], pkey
);
936 state
->dpkey
[0] = state
->spkey
[0] = pkey
[0];
937 state
->dpkey
[1] = state
->spkey
[0] = pkey
[1];
938 state
->dgkey
[0] = state
->sgkey
[0] = 0;
939 state
->dgkey
[1] = state
->sgkey
[0] = 1;
942 state
->previous
= state
->current
;
944 state
->completed
= 0;
945 state
->movecount
= 0;
950 static game_state
*dup_game(game_state
*state
)
952 game_state
*ret
= snew(game_state
);
954 ret
->params
= state
->params
; /* structure copy */
955 ret
->solid
= state
->solid
;
956 ret
->facecolours
= snewn(ret
->solid
->nfaces
, int);
957 memcpy(ret
->facecolours
, state
->facecolours
,
958 ret
->solid
->nfaces
* sizeof(int));
959 ret
->nsquares
= state
->nsquares
;
960 ret
->current
= state
->current
;
961 ret
->squares
= snewn(ret
->nsquares
, struct grid_square
);
962 memcpy(ret
->squares
, state
->squares
,
963 ret
->nsquares
* sizeof(struct grid_square
));
964 ret
->dpkey
[0] = state
->dpkey
[0];
965 ret
->dpkey
[1] = state
->dpkey
[1];
966 ret
->dgkey
[0] = state
->dgkey
[0];
967 ret
->dgkey
[1] = state
->dgkey
[1];
968 ret
->spkey
[0] = state
->spkey
[0];
969 ret
->spkey
[1] = state
->spkey
[1];
970 ret
->sgkey
[0] = state
->sgkey
[0];
971 ret
->sgkey
[1] = state
->sgkey
[1];
972 ret
->previous
= state
->previous
;
973 ret
->angle
= state
->angle
;
974 ret
->completed
= state
->completed
;
975 ret
->movecount
= state
->movecount
;
980 static void free_game(game_state
*state
)
985 static game_state
*solve_game(game_state
*state
, game_aux_info
*aux
,
991 static char *game_text_format(game_state
*state
)
996 static game_ui
*new_ui(game_state
*state
)
1001 static void free_ui(game_ui
*ui
)
1005 static game_state
*make_move(game_state
*from
, game_ui
*ui
,
1006 int x
, int y
, int button
)
1009 int pkey
[2], skey
[2], dkey
[2];
1013 int i
, j
, dest
, mask
;
1016 button
= button
& (~MOD_MASK
| MOD_NUM_KEYPAD
);
1019 * All moves are made with the cursor keys or numeric keypad.
1021 if (button
== CURSOR_UP
|| button
== (MOD_NUM_KEYPAD
| '8'))
1023 else if (button
== CURSOR_DOWN
|| button
== (MOD_NUM_KEYPAD
| '2'))
1025 else if (button
== CURSOR_LEFT
|| button
== (MOD_NUM_KEYPAD
| '4'))
1027 else if (button
== CURSOR_RIGHT
|| button
== (MOD_NUM_KEYPAD
| '6'))
1029 else if (button
== (MOD_NUM_KEYPAD
| '7'))
1030 direction
= UP_LEFT
;
1031 else if (button
== (MOD_NUM_KEYPAD
| '1'))
1032 direction
= DOWN_LEFT
;
1033 else if (button
== (MOD_NUM_KEYPAD
| '9'))
1034 direction
= UP_RIGHT
;
1035 else if (button
== (MOD_NUM_KEYPAD
| '3'))
1036 direction
= DOWN_RIGHT
;
1041 * Find the two points in the current grid square which
1042 * correspond to this move.
1044 mask
= from
->squares
[from
->current
].directions
[direction
];
1047 for (i
= j
= 0; i
< from
->squares
[from
->current
].npoints
; i
++)
1048 if (mask
& (1 << i
)) {
1049 points
[j
*2] = from
->squares
[from
->current
].points
[i
*2];
1050 points
[j
*2+1] = from
->squares
[from
->current
].points
[i
*2+1];
1057 * Now find the other grid square which shares those points.
1058 * This is our move destination.
1061 for (i
= 0; i
< from
->nsquares
; i
++)
1062 if (i
!= from
->current
) {
1066 for (j
= 0; j
< from
->squares
[i
].npoints
; j
++) {
1067 dist
= (SQ(from
->squares
[i
].points
[j
*2] - points
[0]) +
1068 SQ(from
->squares
[i
].points
[j
*2+1] - points
[1]));
1071 dist
= (SQ(from
->squares
[i
].points
[j
*2] - points
[2]) +
1072 SQ(from
->squares
[i
].points
[j
*2+1] - points
[3]));
1086 ret
= dup_game(from
);
1090 * So we know what grid square we're aiming for, and we also
1091 * know the two key points (as indices in both the source and
1092 * destination grid squares) which are invariant between source
1095 * Next we must roll the polyhedron on to that square. So we
1096 * find the indices of the key points within the polyhedron's
1097 * vertex array, then use those in a call to transform_poly,
1098 * and align the result on the new grid square.
1102 align_poly(from
->solid
, &from
->squares
[from
->current
], all_pkey
);
1103 pkey
[0] = all_pkey
[skey
[0]];
1104 pkey
[1] = all_pkey
[skey
[1]];
1106 * Now pkey[0] corresponds to skey[0] and dkey[0], and
1112 * Now find the angle through which to rotate the polyhedron.
1113 * Do this by finding the two faces that share the two vertices
1114 * we've found, and taking the dot product of their normals.
1120 for (i
= 0; i
< from
->solid
->nfaces
; i
++) {
1122 for (j
= 0; j
< from
->solid
->order
; j
++)
1123 if (from
->solid
->faces
[i
*from
->solid
->order
+ j
] == pkey
[0] ||
1124 from
->solid
->faces
[i
*from
->solid
->order
+ j
] == pkey
[1])
1135 for (i
= 0; i
< 3; i
++)
1136 dp
+= (from
->solid
->normals
[f
[0]*3+i
] *
1137 from
->solid
->normals
[f
[1]*3+i
]);
1138 angle
= (float)acos(dp
);
1142 * Now transform the polyhedron. We aren't entirely sure
1143 * whether we need to rotate through angle or -angle, and the
1144 * simplest way round this is to try both and see which one
1145 * aligns successfully!
1147 * Unfortunately, _both_ will align successfully if this is a
1148 * cube, which won't tell us anything much. So for that
1149 * particular case, I resort to gross hackery: I simply negate
1150 * the angle before trying the alignment, depending on the
1151 * direction. Which directions work which way is determined by
1152 * pure trial and error. I said it was gross :-/
1158 if (from
->solid
->order
== 4 && direction
== UP
)
1159 angle
= -angle
; /* HACK */
1161 poly
= transform_poly(from
->solid
,
1162 from
->squares
[from
->current
].flip
,
1163 pkey
[0], pkey
[1], angle
);
1164 flip_poly(poly
, from
->squares
[ret
->current
].flip
);
1165 success
= align_poly(poly
, &from
->squares
[ret
->current
], all_pkey
);
1169 poly
= transform_poly(from
->solid
,
1170 from
->squares
[from
->current
].flip
,
1171 pkey
[0], pkey
[1], angle
);
1172 flip_poly(poly
, from
->squares
[ret
->current
].flip
);
1173 success
= align_poly(poly
, &from
->squares
[ret
->current
], all_pkey
);
1180 * Now we have our rotated polyhedron, which we expect to be
1181 * exactly congruent to the one we started with - but with the
1182 * faces permuted. So we map that congruence and thereby figure
1183 * out how to permute the faces as a result of the polyhedron
1187 int *newcolours
= snewn(from
->solid
->nfaces
, int);
1189 for (i
= 0; i
< from
->solid
->nfaces
; i
++)
1192 for (i
= 0; i
< from
->solid
->nfaces
; i
++) {
1196 * Now go through the transformed polyhedron's faces
1197 * and figure out which one's normal is approximately
1198 * equal to this one.
1200 for (j
= 0; j
< poly
->nfaces
; j
++) {
1206 for (k
= 0; k
< 3; k
++)
1207 dist
+= SQ(poly
->normals
[j
*3+k
] -
1208 from
->solid
->normals
[i
*3+k
]);
1210 if (APPROXEQ(dist
, 0)) {
1212 newcolours
[i
] = ret
->facecolours
[j
];
1216 assert(nmatch
== 1);
1219 for (i
= 0; i
< from
->solid
->nfaces
; i
++)
1220 assert(newcolours
[i
] != -1);
1222 sfree(ret
->facecolours
);
1223 ret
->facecolours
= newcolours
;
1229 * And finally, swap the colour between the bottom face of the
1230 * polyhedron and the face we've just landed on.
1232 * We don't do this if the game is already complete, since we
1233 * allow the user to roll the fully blue polyhedron around the
1234 * grid as a feeble reward.
1236 if (!ret
->completed
) {
1237 i
= lowest_face(from
->solid
);
1238 j
= ret
->facecolours
[i
];
1239 ret
->facecolours
[i
] = ret
->squares
[ret
->current
].blue
;
1240 ret
->squares
[ret
->current
].blue
= j
;
1243 * Detect game completion.
1246 for (i
= 0; i
< ret
->solid
->nfaces
; i
++)
1247 if (ret
->facecolours
[i
])
1249 if (j
== ret
->solid
->nfaces
)
1250 ret
->completed
= ret
->movecount
;
1256 * Align the normal polyhedron with its grid square, to get key
1257 * points for non-animated display.
1263 success
= align_poly(ret
->solid
, &ret
->squares
[ret
->current
], pkey
);
1266 ret
->dpkey
[0] = pkey
[0];
1267 ret
->dpkey
[1] = pkey
[1];
1273 ret
->spkey
[0] = pkey
[0];
1274 ret
->spkey
[1] = pkey
[1];
1275 ret
->sgkey
[0] = skey
[0];
1276 ret
->sgkey
[1] = skey
[1];
1277 ret
->previous
= from
->current
;
1283 /* ----------------------------------------------------------------------
1291 struct game_drawstate
{
1292 int ox
, oy
; /* pixel position of float origin */
1295 static void find_bbox_callback(void *ctx
, struct grid_square
*sq
)
1297 struct bbox
*bb
= (struct bbox
*)ctx
;
1300 for (i
= 0; i
< sq
->npoints
; i
++) {
1301 if (bb
->l
> sq
->points
[i
*2]) bb
->l
= sq
->points
[i
*2];
1302 if (bb
->r
< sq
->points
[i
*2]) bb
->r
= sq
->points
[i
*2];
1303 if (bb
->u
> sq
->points
[i
*2+1]) bb
->u
= sq
->points
[i
*2+1];
1304 if (bb
->d
< sq
->points
[i
*2+1]) bb
->d
= sq
->points
[i
*2+1];
1308 static struct bbox
find_bbox(game_params
*params
)
1313 * These should be hugely more than the real bounding box will
1316 bb
.l
= 2.0F
* (params
->d1
+ params
->d2
);
1317 bb
.r
= -2.0F
* (params
->d1
+ params
->d2
);
1318 bb
.u
= 2.0F
* (params
->d1
+ params
->d2
);
1319 bb
.d
= -2.0F
* (params
->d1
+ params
->d2
);
1320 enum_grid_squares(params
, find_bbox_callback
, &bb
);
1325 static void game_size(game_params
*params
, int *x
, int *y
)
1327 struct bbox bb
= find_bbox(params
);
1328 *x
= (int)((bb
.r
- bb
.l
+ 2*solids
[params
->solid
]->border
) * GRID_SCALE
);
1329 *y
= (int)((bb
.d
- bb
.u
+ 2*solids
[params
->solid
]->border
) * GRID_SCALE
);
1332 static float *game_colours(frontend
*fe
, game_state
*state
, int *ncolours
)
1334 float *ret
= snewn(3 * NCOLOURS
, float);
1336 frontend_default_colour(fe
, &ret
[COL_BACKGROUND
* 3]);
1338 ret
[COL_BORDER
* 3 + 0] = 0.0;
1339 ret
[COL_BORDER
* 3 + 1] = 0.0;
1340 ret
[COL_BORDER
* 3 + 2] = 0.0;
1342 ret
[COL_BLUE
* 3 + 0] = 0.0;
1343 ret
[COL_BLUE
* 3 + 1] = 0.0;
1344 ret
[COL_BLUE
* 3 + 2] = 1.0;
1346 *ncolours
= NCOLOURS
;
1350 static game_drawstate
*game_new_drawstate(game_state
*state
)
1352 struct game_drawstate
*ds
= snew(struct game_drawstate
);
1353 struct bbox bb
= find_bbox(&state
->params
);
1355 ds
->ox
= (int)(-(bb
.l
- state
->solid
->border
) * GRID_SCALE
);
1356 ds
->oy
= (int)(-(bb
.u
- state
->solid
->border
) * GRID_SCALE
);
1361 static void game_free_drawstate(game_drawstate
*ds
)
1366 static void game_redraw(frontend
*fe
, game_drawstate
*ds
, game_state
*oldstate
,
1367 game_state
*state
, int dir
, game_ui
*ui
,
1368 float animtime
, float flashtime
)
1371 struct bbox bb
= find_bbox(&state
->params
);
1376 game_state
*newstate
;
1379 draw_rect(fe
, 0, 0, (int)((bb
.r
-bb
.l
+2.0F
) * GRID_SCALE
),
1380 (int)((bb
.d
-bb
.u
+2.0F
) * GRID_SCALE
), COL_BACKGROUND
);
1386 * This is an Undo. So reverse the order of the states, and
1387 * run the roll timer backwards.
1395 animtime
= ROLLTIME
- animtime
;
1401 square
= state
->current
;
1402 pkey
= state
->dpkey
;
1403 gkey
= state
->dgkey
;
1405 angle
= state
->angle
* animtime
/ ROLLTIME
;
1406 square
= state
->previous
;
1407 pkey
= state
->spkey
;
1408 gkey
= state
->sgkey
;
1413 for (i
= 0; i
< state
->nsquares
; i
++) {
1416 for (j
= 0; j
< state
->squares
[i
].npoints
; j
++) {
1417 coords
[2*j
] = ((int)(state
->squares
[i
].points
[2*j
] * GRID_SCALE
)
1419 coords
[2*j
+1] = ((int)(state
->squares
[i
].points
[2*j
+1]*GRID_SCALE
)
1423 draw_polygon(fe
, coords
, state
->squares
[i
].npoints
, TRUE
,
1424 state
->squares
[i
].blue ? COL_BLUE
: COL_BACKGROUND
);
1425 draw_polygon(fe
, coords
, state
->squares
[i
].npoints
, FALSE
, COL_BORDER
);
1429 * Now compute and draw the polyhedron.
1431 poly
= transform_poly(state
->solid
, state
->squares
[square
].flip
,
1432 pkey
[0], pkey
[1], angle
);
1435 * Compute the translation required to align the two key points
1436 * on the polyhedron with the same key points on the current
1439 for (i
= 0; i
< 3; i
++) {
1442 for (j
= 0; j
< 2; j
++) {
1447 state
->squares
[square
].points
[gkey
[j
]*2+i
];
1452 tc
+= (grid_coord
- poly
->vertices
[pkey
[j
]*3+i
]);
1457 for (i
= 0; i
< poly
->nvertices
; i
++)
1458 for (j
= 0; j
< 3; j
++)
1459 poly
->vertices
[i
*3+j
] += t
[j
];
1462 * Now actually draw each face.
1464 for (i
= 0; i
< poly
->nfaces
; i
++) {
1468 for (j
= 0; j
< poly
->order
; j
++) {
1469 int f
= poly
->faces
[i
*poly
->order
+ j
];
1470 points
[j
*2] = (poly
->vertices
[f
*3+0] -
1471 poly
->vertices
[f
*3+2] * poly
->shear
);
1472 points
[j
*2+1] = (poly
->vertices
[f
*3+1] -
1473 poly
->vertices
[f
*3+2] * poly
->shear
);
1476 for (j
= 0; j
< poly
->order
; j
++) {
1477 coords
[j
*2] = (int)floor(points
[j
*2] * GRID_SCALE
) + ds
->ox
;
1478 coords
[j
*2+1] = (int)floor(points
[j
*2+1] * GRID_SCALE
) + ds
->oy
;
1482 * Find out whether these points are in a clockwise or
1483 * anticlockwise arrangement. If the latter, discard the
1484 * face because it's facing away from the viewer.
1486 * This would involve fiddly winding-number stuff for a
1487 * general polygon, but for the simple parallelograms we'll
1488 * be seeing here, all we have to do is check whether the
1489 * corners turn right or left. So we'll take the vector
1490 * from point 0 to point 1, turn it right 90 degrees,
1491 * and check the sign of the dot product with that and the
1492 * next vector (point 1 to point 2).
1495 float v1x
= points
[2]-points
[0];
1496 float v1y
= points
[3]-points
[1];
1497 float v2x
= points
[4]-points
[2];
1498 float v2y
= points
[5]-points
[3];
1499 float dp
= v1x
* v2y
- v1y
* v2x
;
1505 draw_polygon(fe
, coords
, poly
->order
, TRUE
,
1506 state
->facecolours
[i
] ? COL_BLUE
: COL_BACKGROUND
);
1507 draw_polygon(fe
, coords
, poly
->order
, FALSE
, COL_BORDER
);
1511 draw_update(fe
, 0, 0, (int)((bb
.r
-bb
.l
+2.0F
) * GRID_SCALE
),
1512 (int)((bb
.d
-bb
.u
+2.0F
) * GRID_SCALE
));
1515 * Update the status bar.
1518 char statusbuf
[256];
1520 sprintf(statusbuf
, "%sMoves: %d",
1521 (state
->completed ?
"COMPLETED! " : ""),
1522 (state
->completed ? state
->completed
: state
->movecount
));
1524 status_bar(fe
, statusbuf
);
1528 static float game_anim_length(game_state
*oldstate
,
1529 game_state
*newstate
, int dir
, game_ui
*ui
)
1534 static float game_flash_length(game_state
*oldstate
,
1535 game_state
*newstate
, int dir
, game_ui
*ui
)
1540 static int game_wants_statusbar(void)
1545 static int game_timing_state(game_state
*state
)
1551 #define thegame cube
1554 const struct game thegame
= {
1555 "Cube", "games.cube",
1562 TRUE
, game_configure
, custom_params
,
1571 FALSE
, game_text_format
,
1578 game_free_drawstate
,
1582 game_wants_statusbar
,
1583 FALSE
, game_timing_state
,