[zx-fizzbuzz] / fizzbuzz.s

;;; -*-asm-*-
;;;
;;; Best not to ask why.

	;; Look at the buffer and decide what to do.
again:	ld	e, 0

	;; First, decide whether it's a multiple of three.  This is a bit
	;; fiddly.
	ld	a, (len)
	ld	b, a
	ld	hl, buf
	xor	a

	;; Main `mod 3' loop.  Load a byte and add it into the accumulator in
	;; decimal.
mod3:	ld	c, (hl)
	inc	hl
	add	a, c
	daa
	jr	nc, mod3_1
	call	squish
	add	a, 1
	daa
mod3_1:	djnz	mod3

	call	squish
	call	squish

	and	a
	jr	z, prfizz
	cp	3
	jr	z, prfizz
	cp	6
	jr	z, prfizz
	cp	9
	jr	nz, nofizz

prfizz:	ld	hl, fizz
	call	print
	inc	e

	;; Next, decide whether it's a multiple of five.  This is easier.
nofizz:	ld	a, (buf)
	and	0x0f
	jr	z, prbuzz
	cp	5
	jr	nz, nobuzz

prbuzz:	ld	hl, buzz
	call	print
	jr	prnl

	;; Not a multiple of five.  Skip ahead if it was a multiple of three.
nobuzz:	ld	a, e
	and	a
	jr	nz, prnl

	;; OK, so just print the value.
	ld	hl, buf - 1
	ld	bc, (len)
	add	hl, bc
	ld	b, c

	ld	a, (hl)
	ld	d, a
	srl	a
	srl	a
	srl	a
	srl	a
	jr	z, skiplz
	fixdig
	print_a
skiplz:	ld	a, d
	and	0x0f
	fixdig
	print_a
	dec	b
	jr	z, prnl

prdig:	dec	hl
	ld	a, (hl)
	ld	d, a
	srl	a
	srl	a
	srl	a
	srl	a
	fixdig
	print_a
	ld	a, d
	and	0x0f
	fixdig
	print_a
	djnz	prdig

	;; Print the newline.
prnl:	ld	a, spc
	print_a

	;; Increment the counter.
	ld	hl, buf
	ld	a, (len)
	ld	b, a
	scf
incr:	ld	a, (hl)
	adc	a, 0
	daa
	ld	(hl), a
	jp	nc, again
	inc	hl
	djnz	incr

	;; Carry out.
	ld	(hl), 1
	ld	hl, len
	inc	(hl)
	jp	again

squish:
	;; Add the two halves of a.
	ld	c, a
	and	0x0f
	srl	c
	srl	c
	srl	c
	srl	c
	add	a, c
	daa
	ret

print:
	;; Print the string at hl.
	ld	a, (hl)
	endstrp
	ret	z
	print_a
	inc	hl
	jr	print

	;; Initial state.  The buffer notionally continues for another 254
	;; bytes, but there's no point in including them in the image.
len:	db	1, 0
buf:	db	1
Commit	Line	Data
a221d644 MW	1	;;; --asm--
	2	;;;
	3	;;; Best not to ask why.
	4
a221d644 MW	5	;; Look at the buffer and decide what to do.
	6	again: ld e, 0
	7
	8	;; First, decide whether it's a multiple of three. This is a bit
	9	;; fiddly.
	10	ld a, (len)
	11	ld b, a
	12	ld hl, buf
	13	xor a
	14
	15	;; Main `mod 3' loop. Load a byte and add it into the accumulator in
	16	;; decimal.
	17	mod3: ld c, (hl)
	18	inc hl
	19	add a, c
	20	daa
	21	jr nc, mod3_1
	22	call squish
	23	add a, 1
	24	daa
	25	mod3_1: djnz mod3
	26
	27	call squish
	28	call squish
	29
64b6fca5	30	and a
a221d644 MW	31	jr z, prfizz
	32	cp 3
	33	jr z, prfizz
	34	cp 6
	35	jr z, prfizz
	36	cp 9
	37	jr nz, nofizz
	38
	39	prfizz: ld hl, fizz
	40	call print
	41	inc e
	42
	43	;; Next, decide whether it's a multiple of five. This is easier.
	44	nofizz: ld a, (buf)
	45	and 0x0f
	46	jr z, prbuzz
	47	cp 5
	48	jr nz, nobuzz
	49
	50	prbuzz: ld hl, buzz
	51	call print
	52	jr prnl
	53
	54	;; Not a multiple of five. Skip ahead if it was a multiple of three.
	55	nobuzz: ld a, e
64b6fca5	56	and a
a221d644 MW	57	jr nz, prnl
	58
	59	;; OK, so just print the value.
a221d644	60	ld hl, buf - 1
0bf6b60e	61	ld bc, (len)
a221d644 MW	62	add hl, bc
	63	ld b, c
	64
	65	ld a, (hl)
	66	ld d, a
	67	srl a
	68	srl a
	69	srl a
	70	srl a
	71	jr z, skiplz
64b6fca5 MW	72	fixdig
64b6fca5 MW	73	print_a
a221d644 MW	74	skiplz: ld a, d
a221d644 MW	75	and 0x0f
64b6fca5 MW	76	fixdig
64b6fca5 MW	77	print_a
a221d644 MW	78	dec b
	79	jr z, prnl
	80
	81	prdig: dec hl
	82	ld a, (hl)
	83	ld d, a
	84	srl a
	85	srl a
	86	srl a
	87	srl a
64b6fca5 MW	88	fixdig
64b6fca5 MW	89	print_a
a221d644 MW	90	ld a, d
a221d644 MW	91	and 0x0f
64b6fca5 MW	92	fixdig
64b6fca5 MW	93	print_a
a221d644 MW	94	djnz prdig
	95
	96	;; Print the newline.
64b6fca5 MW	97	prnl: ld a, spc
64b6fca5 MW	98	print_a
a221d644 MW	99
	100	;; Increment the counter.
	101	ld hl, buf
	102	ld a, (len)
	103	ld b, a
	104	scf
	105	incr: ld a, (hl)
	106	adc a, 0
	107	daa
	108	ld (hl), a
	109	jp nc, again
	110	inc hl
	111	djnz incr
	112
	113	;; Carry out.
a221d644	114	ld (hl), 1
b4fd0180 MW	115	ld hl, len
b4fd0180 MW	116	inc (hl)
a221d644 MW	117	jp again
	118
	119	squish:
	120	;; Add the two halves of a.
	121	ld c, a
	122	and 0x0f
	123	srl c
	124	srl c
	125	srl c
	126	srl c
	127	add a, c
	128	daa
	129	ret
	130
	131	print:
	132	;; Print the string at hl.
	133	ld a, (hl)
64b6fca5	134	endstrp
a221d644	135	ret z
64b6fca5	136	print_a
a221d644 MW	137	inc hl
	138	jr print
	139
64b6fca5 MW	140	;; Initial state. The buffer notionally continues for another 254
64b6fca5 MW	141	;; bytes, but there's no point in including them in the image.
0bf6b60e	142	len: db 1, 0
64b6fca5	143	buf: db 1