## stage of a pipeline, where we actually wanted the status of the first. So
## we write that to another pipe (fd 5) and pick it out using command
## substitution.
+copy () { while IFS= read -r line; do printf "%s %s\n" "$1" "$line"; done; }
rc=$(
- { { { { set +e; $lbuf "$cmd" "$@"; echo $? >&5; } |
- while IFS= read line; do echo "| $line"; done >&4; } 2>&1 |
- while IFS= read line; do echo "* $line"; done >&4; } 4>&1 |
+ { { { { set +e; $lbuf "$cmd" "$@" 3>&- 4>&- 5>&-; echo $? >&5; } |
+ copy "|" >&4; } 2>&1 |
+ copy "*" >&4; } 4>&1 |
cat -u >&3; } 5>&1 </dev/null
)
###--------------------------------------------------------------------------
### Delete old log files if there are too many.
-## Count up the logfiles.
-nlog=0
+## Find out the tails of the logfile names. We assume that we're responsible
+## for all of these, and therefore that they're nicely formed.
+logs="" nlog=0
for i in "$logdir/$tag".*; do
if [ ! -f "$i" ]; then continue; fi
- nlog=$(( nlog + 1 ))
+ nlog=$(( $nlog + 1 ))
+ logs="$logs ${i#$logdir/$tag.}"
done
## If there are too many, go through and delete some early ones.
if [ $nlog -gt $maxlog ]; then
- n=$(( nlog - maxlog ))
- for i in "$logdir/$tag".*; do
- if [ ! -f "$i" ]; then continue; fi
- rm -f "$i"
- n=$(( n - 1 ))
+ n=$(( $nlog - $maxlog ))
+ for i in $logs; do echo $i; done | sort -t# -k1,1 -k2n | while read i; do
+ rm -f "$logdir/$tag.$i"
+ n=$(( $n - 1 ))
if [ $n -eq 0 ]; then break; fi
done
fi