X-Git-Url: https://git.distorted.org.uk/~mdw/catacomb/blobdiff_plain/8e663045cd18e14e99affd3f904170dc686fd76c..HEAD:/math/gfreduce.c diff --git a/math/gfreduce.c b/math/gfreduce.c index 96e0cedf..f29c1048 100644 --- a/math/gfreduce.c +++ b/math/gfreduce.c @@ -49,14 +49,15 @@ DA_DECL(instr_v, gfreduce_instr); * sense fast. Here, we do efficient reduction modulo sparse polynomials. * (It works for arbitrary polynomials, but isn't efficient for dense ones.) * - * Suppose that %$p(x) = x^n + p'(x) = \sum_{0\le if & f_fip) && w < g->r->lim) { + g->fip = DA_LEN(&g->iv); + g->f |= f_fip; + } + + /* --- Actually emit the instruction --- */ + INSTR(g, GFRI_LOAD, w); g->f |= f_load; g->w = w; @@ -160,6 +182,7 @@ void gfreduce_create(gfreduce *r, mp *p) /* --- Sort out the easy stuff --- */ + g.r = r; d = mp_bits(p); assert(d); d--; r->lim = d/MPW_BITS; dw = d%MPW_BITS; @@ -234,9 +257,20 @@ void gfreduce_create(gfreduce *r, mp *p) INSTR(&g, GFRI_STORE, g.w); } + /* --- Copy the instruction vector. + * + * If we've not set a final-pass offset yet then now would be an excellent + * time. Obviously it should be right at the end, because there's nothing + * for a final pass to do. + */ + r->in = DA_LEN(&g.iv); r->iv = xmalloc(r->in * sizeof(gfreduce_instr)); memcpy(r->iv, DA(&g.iv), r->in * sizeof(gfreduce_instr)); + + if (!(g.f & f_fip)) g.fip = DA_LEN(&g.iv); + r->fiv = r->iv + g.fip; + DA_DESTROY(&g.iv); } @@ -244,6 +278,7 @@ void gfreduce_create(gfreduce *r, mp *p) #undef f_lsr #undef f_load +#undef f_fip /* --- @gfreduce_destroy@ --- * * @@ -262,7 +297,7 @@ void gfreduce_destroy(gfreduce *r) /* --- @gfreduce_dump@ --- * * - * Arguments: @gfreduce *r@ = structure to dump + * Arguments: @const gfreduce *r@ = structure to dump * @FILE *fp@ = file to dump on * * Returns: --- @@ -270,7 +305,7 @@ void gfreduce_destroy(gfreduce *r) * Use: Dumps a reduction context. */ -void gfreduce_dump(gfreduce *r, FILE *fp) +void gfreduce_dump(const gfreduce *r, FILE *fp) { size_t i; @@ -279,16 +314,20 @@ void gfreduce_dump(gfreduce *r, FILE *fp) (unsigned long)r->lim, (unsigned long)r->mask); for (i = 0; i < r->in; i++) { static const char *opname[] = { "load", "lsl", "lsr", "store" }; + if (&r->iv[i] == r->fiv) + fputs("final:\n", fp); assert(r->iv[i].op < N(opname)); fprintf(fp, " %s %lu\n", opname[r->iv[i].op], (unsigned long)r->iv[i].arg); } + if (&r->iv[i] == r->fiv) + fputs("final:\n", fp); } /* --- @gfreduce_do@ --- * * - * Arguments: @gfreduce *r@ = reduction context + * Arguments: @const gfreduce *r@ = reduction context * @mp *d@ = destination * @mp *x@ = source * @@ -311,7 +350,7 @@ static void run(const gfreduce_instr *i, const gfreduce_instr *il, } } -mp *gfreduce_do(gfreduce *r, mp *d, mp *x) +mp *gfreduce_do(const gfreduce *r, mp *d, mp *x) { mpw *v, *vl; const gfreduce_instr *il; @@ -340,7 +379,7 @@ mp *gfreduce_do(gfreduce *r, mp *d, mp *x) while (*vl & r->mask) { z = *vl & r->mask; *vl &= ~r->mask; - run(r->iv, il, vl, z); + run(r->fiv, il, vl, z); } } } @@ -353,20 +392,26 @@ mp *gfreduce_do(gfreduce *r, mp *d, mp *x) /* --- @gfreduce_sqrt@ --- * * - * Arguments: @gfreduce *r@ = pointer to reduction context + * Arguments: @const gfreduce *r@ = pointer to reduction context * @mp *d@ = destination * @mp *x@ = some polynomial * * Returns: The square root of @x@ modulo @r->p@, or null. */ -mp *gfreduce_sqrt(gfreduce *r, mp *d, mp *x) +mp *gfreduce_sqrt(const gfreduce *r, mp *d, mp *x) { mp *y = MP_COPY(x); mp *z, *spare = MP_NEW; unsigned long m = mp_bits(r->p) - 1; unsigned long i; + /* --- This is pretty easy --- * + * + * Note that %$x = x^{2^m}$%; therefore %$(x^{2^{m-1}})^2 = x^{2^m} = x$%, + * so %$x^{2^{m-1}}$% is the square root we seek. + */ + for (i = 0; i < m - 1; i++) { mp *t = gf_sqr(spare, y); spare = y; @@ -385,14 +430,17 @@ mp *gfreduce_sqrt(gfreduce *r, mp *d, mp *x) /* --- @gfreduce_trace@ --- * * - * Arguments: @gfreduce *r@ = pointer to reduction context + * Arguments: @const gfreduce *r@ = pointer to reduction context * @mp *x@ = some polynomial * * Returns: The trace of @x@. (%$\Tr(x)=x + x^2 + \cdots + x^{2^{m-1}}$% - * if %$x \in \gf{2^m}$%). + * if %$x \in \gf{2^m}$%). Since the trace is invariant under + * the Frobenius automorphism (i.e., %$\Tr(x)^2 = \Tr(x)$%), it + * must be an element of the base field, i.e., %$\gf{2}$%, and + * we only need a single bit to represent it. */ -int gfreduce_trace(gfreduce *r, mp *x) +int gfreduce_trace(const gfreduce *r, mp *x) { mp *y = MP_COPY(x); mp *spare = MP_NEW; @@ -414,7 +462,7 @@ int gfreduce_trace(gfreduce *r, mp *x) /* --- @gfreduce_halftrace@ --- * * - * Arguments: @gfreduce *r@ = pointer to reduction context + * Arguments: @const gfreduce *r@ = pointer to reduction context * @mp *d@ = destination * @mp *x@ = some polynomial * @@ -423,7 +471,7 @@ int gfreduce_trace(gfreduce *r, mp *x) * if %$x \in \gf{2^m}$% with %$m$% odd). */ -mp *gfreduce_halftrace(gfreduce *r, mp *d, mp *x) +mp *gfreduce_halftrace(const gfreduce *r, mp *d, mp *x) { mp *y = MP_COPY(x); mp *spare = MP_NEW; @@ -446,27 +494,82 @@ mp *gfreduce_halftrace(gfreduce *r, mp *d, mp *x) /* --- @gfreduce_quadsolve@ --- * * - * Arguments: @gfreduce *r@ = pointer to reduction context + * Arguments: @const gfreduce *r@ = pointer to reduction context * @mp *d@ = destination * @mp *x@ = some polynomial * - * Returns: A polynomial @y@ such that %$y^2 + y = x$%, or null. + * Returns: A polynomial @z@ such that %$z^2 + z = x$%, or null. + * + * Use: Solves quadratic equations in a field with characteristic 2. + * Suppose we have an equation %$y^2 + A y + B = 0$% where + * %$A \ne 0$%. (If %$A = 0$% then %$y = \sqrt{B}$% and you + * want @gfreduce_sqrt@ instead.) Use this function to solve + * %$z^2 + z = B/A^2$%; then set %$y = A z$%, since + * %$y^2 + y = A^2 z^2 + A^2 z = A^2 (z^2 + z) = B$% as + * required. + * + * The two roots are %$z$% and %$z + 1$%; this function always + * returns the one with zero scalar coefficient. */ -mp *gfreduce_quadsolve(gfreduce *r, mp *d, mp *x) +mp *gfreduce_quadsolve(const gfreduce *r, mp *d, mp *x) { unsigned long m = mp_bits(r->p) - 1; mp *t; + /* --- About the solutions --- * + * + * Factor %$z^2 + z = z (z + 1)$%. Therefore, if %$z^2 + z = x$% and + * %$z' = z + 1$% then %$z'^2 + z' = z^2 + 1 + z + 1 = z^2 + z$%, so + * %$z + 1$% is the other solution. + * + * A solution exists if and only if %$\Tr(x) = 0$%. To see the `only if' + * implication, recall that the trace function is linear, and hence + * $%\Tr(z^2 + z) = \Tr(z)^2 + \Tr(z) = \Tr(z) + \Tr(z) = 0$%. The `if' + * direction will be proven using explicit constructions captured in the + * code below. + */ + MP_COPY(x); - if (m & 1) + if (m & 1) { + + /* --- A short-cut for fields with odd degree --- + * + * The method below works in all binary fields, but there's a quicker way + * which works whenever the degree is odd. The half-trace is + * %$z = \sum_{0\le i\le (m-1)/2} x^{2^{2i}}$%. Then %$z^2 + z = {}$% + * %$\sum_{0\le i\le (m-1)/2} (x^{2^{2i}} + x^{2^{2i+1}}) = {}$% + * %$\Tr(x) + x^{2^m} = \Tr(x) + x$%. This therefore gives us the + * solution we want whenever %$\Tr(x) = 0$%. + */ + d = gfreduce_halftrace(r, d, x); - else { + } else { mp *z, *w, *rho = MP_NEW; mp *spare = MP_NEW; grand *fr = fibrand_create(0); unsigned long i; + /* --- Unpicking the magic --- * + * + * Choose %$\rho \inr \gf{2^m}$% with %$\Tr(\rho) = 1$%. Let + * %$z = \sum_{0\le iv[0] &= ~(mpw)1; return (d); } /* --- @gfreduce_exp@ --- * * - * Arguments: @gfreduce *gr@ = pointer to reduction context + * Arguments: @const gfreduce *gr@ = pointer to reduction context * @mp *d@ = fake destination * @mp *a@ = base * @mp *e@ = exponent @@ -512,7 +628,7 @@ mp *gfreduce_quadsolve(gfreduce *r, mp *d, mp *x) * Returns: Result, %$a^e \bmod m$%. */ -mp *gfreduce_exp(gfreduce *gr, mp *d, mp *a, mp *e) +mp *gfreduce_exp(const gfreduce *gr, mp *d, mp *a, mp *e) { mp *x = MP_ONE; mp *spare = (e->f & MP_BURN) ? MP_NEWSEC : MP_NEW; @@ -539,8 +655,6 @@ mp *gfreduce_exp(gfreduce *gr, mp *d, mp *a, mp *e) #ifdef TEST_RIG -#define MP(x) mp_readstring(MP_NEW, #x, 0, 0) - static int vreduce(dstr *v) { mp *d = *(mp **)v[0].buf;