/* This here is the hard part.
*
- * Let w = PIECEWD, let n = NPIECE, and let B = 2^w. Wwe must have
+ * Let w = PIECEWD, let n = NPIECE, and let B = 2^w. We must have
* B^(n-1) <= l < B^n.
*
* The argument MU contains pieces of the quantity ยต = floor(B^2n/l), which